If Jerry got 40 dollars every month, how much would he have a year?

Mathematics

1 answer:

zysi [14]3 years ago

4 0

Jerry would have in a year $480

You might be interested in

Please show work and thank youuu

Papessa [141]

Answer:

Step-by-step explanation:

As the opposing side of the angle and the hypotenuse are given, take the sine ratio of the angle.

sin 45° = x/16
1/√2 = x/16
x = 16 / √2
x = 16√2 / 2
<u>x = 8√2</u>

8 0

2 years ago

Read 2 more answers

How to put 35.99 in a mix number

Anon25 [30]

35 99/100 (35 wholes 99 over 100)

6 0

4 years ago

Guys, I beg you! How do you do these factoring quadratic equations!

Valentin [98]

Times the x’a together and x*10 then 2*x and 2*10

5 0

2 years ago

Read 2 more answers

How to solve this linear equation step by step please

mote1985 [20]

$\bf \cfrac{3}{c^2-4c}-\cfrac{9}{2c^2+3c}=\cfrac{2}{2c^2-5c-12}\\\\\\ 
\begin{cases}
c^2-4c=&c(c-4)\\
2c^2+3c=&c(2c+3)\\\\
2c^2-5c-12=
&(2c+3)(c-4)
\end{cases}\\\\
-------------------------------\\\\
\textit{therefore, our LCD for the \underline{left-side} will have to be }\underline{c(c-4)(2c+3)}\\\\
-------------------------------\\\\$

$\bf \cfrac{3}{c(c-4)}-\cfrac{9}{c(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{3(2c+3)-9(c-4)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-(9c-36)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-9c+36}{1}=\cfrac{2[c(c-4)(2c+3)]}{(2c+3)(c-4)}
\\\\\\
-3c+45=2c\implies 45=5c\implies \cfrac{45}{5}=c\implies 9=c$

7 0

3 years ago

The gcf of 14 and 22

Finger [1]

The GCF is 2
Hope this helps!

8 0

3 years ago

Read 2 more answers