The general form of a solution of the differential equation is already provided for us:
where 
. We now want to find a solution 
such that 
and 
. Therefore, all we need to do is find the constants 
and 
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative 
first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute 
into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.
Answer:
300 phones the company activated in one minute
As per unitary method, calculation been done to find the value of single unit from the value of multiple units.
So, she is dividing the total number of phone activated by number of minutes taken to activate to find phone activate in one minute.
Step-by-step explanation:
Here is the correct question: Meg wants to find how many phones the company activated in one minute. Explain why meg can use 15000 divided by 50 to find the answer.
As per unitary method, calculation been done to find the value of single unit from the value of multiple units.
Therefore, in the above question Meg knew the number of total phone activated by company in 50 minutes, which is 15000.
Now, she want to find how many phones the company activates in one minute.
So, she is dividing the total number of phone activated by number of minutes taken to activate to find phone activate in one minute.
Phones the company activated in one minute= 
∴ 300 phones the company activated in one minute.
Answer:
y=140-10x is what i got as my answer
Answer:
No, (3, 9) is not a solution of the system.
Step-by-step explanation:
y=3x
2x-y=6
-----------
3(3)=9
2(3)-9=6-9=-3, not 6
