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kirza4 [7]
3 years ago
10

Free points, One last question, 3k+16=8+5k​

Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0

Answer:

\Huge \boxed{k=4}

Step-by-step explanation:

\sf 3k+16=8+5k

Subtracting 3k and 8 from both sides.

\sf 16-8=5k-3k

\sf 8=2k

Dividing both sides by 2.

\sf \displaystyle  \frac{8}{2} =\frac{2k}{2}

\sf 4=k

Tema [17]3 years ago
3 0

Answer:

k = 4

Step-by-step explanation:

Hello!

3k + 16 = 8 + 5k

Subtract 3k from both sides

16 = 8 + 2k

Subtract 8 from both sides

8 = 2k

Divide both sides by 2

4 = k

The answer is 4

Hope this Helps!

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Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E
bazaltina [42]

Answer:

<u> x = 16</u>

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

Given:

m∠ABC = 84  and m∠ABE = 3x − 6

So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42

∴ 3x - 6 = 42

Solve for x

3x = 42 + 6 = 48

x = 48/3 = 16

<u>∴ x = 16</u>

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