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krek1111 [17]
4 years ago
5

Point Z is equidistant from the vertices of ΔTUV.

Mathematics
2 answers:
Naily [24]4 years ago
4 0

Answer:

option C. Angle BTZ Is-congruent-to Angle BUZ

Step-by-step explanation:

nadya68 [22]4 years ago
3 0

Answer:

option C. Angle BTZ Is-congruent-to Angle BUZ

Step-by-step explanation:

Point Z is equidistant from the vertices of triangle T U V

So, ZT = ZU = ZV

When ZT = ZU  ∴ ΔZTU is an isosceles triangle ⇒ ∠TUZ=∠UTZ

When ZT = ZV  ∴  ΔZTV is an isosceles triangle ⇒ ∠ZTV=∠ZVT

When ZU = ZV  ∴ ΔZUV is an isosceles triangle ⇒ ∠ZUV=∠ZVU

From the figure ∠BTZ is the same as ∠UTZ

And ∠BUZ is the same as ∠TUZ

So, the statement that must be true is option C

C.Angle BTZ Is-congruent-to Angle BUZ

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