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sasho [114]
3 years ago
5

Someone please help me with this

Mathematics
1 answer:
Vesnalui [34]3 years ago
5 0
I dont know the answer but i would say b but dont take my word for it.
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3 exponet 8×4+9÷1×56+57
nika2105 [10]
You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3
4 0
3 years ago
Read 2 more answers
Help please if m1 = 72 then find the value of m3​
Dima020 [189]

m<3 =72°

This is because m<1 and m<3 are vertically opposite.

8 0
2 years ago
Which point is a solution to the inequality shown in this graph?
sergey [27]

Good morning

Answer:

B: (1, 5)

Step-by-step explanation:

This graph shows the solutions to the inequality: y > (1/3)x - 2

Since, 5 > (1/3)×1 - 2 then the point (1 ,5) is a solution to the inequality.

____________________________

:)

6 0
3 years ago
State the domain of the relation R{(-3,3), (1,1), (0,2),(1,-4),(5,-1)} and then State the range of the relation R={(-3,3), (1,1)
harina [27]
The range is the Y value and the Domain is the X value.
6 0
3 years ago
Given the first type of plot indicated in each pair, which of the second plots could not always be generated from it?
Kisachek [45]

Answer:

d. box plot, stem and leaf

Step-by-step explanation:

The box plot depicts the five number summary minimum, 1st quartile, median, third quartile and maximum while stem and leaf plot shows every observation in data. So, when the box plot is given, we can't generate stem and leaf plot for the data because we don't have sufficient information in this scenario i.e., we don't have every data value to generate stem and leaf plot. Whereas, If the stem and leaf plot is given first then we can generate box plot from it because we have every data value to compute 5-number summary to generate box plot.

a. From dot plot, the histogram can be generated because dot plot represents every data value in the form of dots and from every data value, we can generate histogram.

b. From dot plot, the stem and leaf plot can be generated because dot plot represents every data value in the form of dots and from every data value, we can generate stem and leaf plot.

c. From stem and leaf plot, the dot plot can be generated because stem plot represents every data value in the form of stem and leaf i.e. 12 can be represented as 1 for a stem and 2 for a leaf (1  2)  and so, from every data value we can generate dot plot.

d. From box plot, the stem and leaf plot can't be generated and the reason is explained in first paragraph. So, when the first type of plot is box plot then from it second plot stem and leaf plot can't be generated.

6 0
3 years ago
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