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3 years ago

If 5 students had to share 7 brownies, how much would each student get?

Mathematics

1 answer:

Furkat [3]3 years ago

7 0

It would be 35 because 7x5 equals 35

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Which is a perfect square? 6^1 6^2 6^3 6^4

k0ka [10]

Should be 6^3.

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3 years ago

Please help. Is algebra. PLEASE HELP NO LINKS OR FILES. I don't want links.

alexandr1967 [171]

9514 1404 393

Answer:

9n^4

Step-by-step explanation:

The divisor and quotient can be interchanged to find the divisor:

$\dfrac{18n^6+27n^5-36n^4}{2n^2+3n-4}=\boxed{\text{Blank 1}}$

Such division is carried out by first finding the quotient of the highest-degree terms:

$\dfrac{18n^6}{2n^2}=\dfrac{18}{2}n^{6-2}=9n^4$

This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...

9n^4

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The attachment shows the long division.

7 0

3 years ago

Kate is making pizza she put 8 ounces of cheese on each pizza if she has 4 20ounce packages of cheese how many pieces can she ma

dexar [7]

Answer:

60 pizzas

Step-by-step explanation:

4 0

4 years ago

5 5/8 - 3 2/8 is equal to 2 3/8. True or False?

jek_recluse [69]

Answer:

True

Step-by-step explanation:

5/8-2/8=3/8

5-3=2

2+3/8=2 3/8

5 0

4 years ago

Read 2 more answers

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$