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Vesnalui [34]
3 years ago
9

Can the division expression 4÷15 be shown as a fraction explain

Mathematics
1 answer:
Levart [38]3 years ago
8 0
Yes 4/15 is the answer
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During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s . What was her average acceleration du
GREYUIT [131]

Answer:

The average acceleration of the cyclist was 0.6 m/s².

Step-by-step explanation:

Acceleration:

The rate change of velocity per unit time is call the acceleration of the object.

a=\frac{v-u}t

u= initial velocity

v= final velocity

t= time taken change of velocity.

During the final 5 seconds of a race cyclist increased her velocity from 4m/s to 7 m/s

Here v= 7 m/s and u=4 m/s t=5 seconds

\therefore a=\frac{7\ m/s-4 \ m/s}{5s}

     =\frac{3}{5} \ m/s^2

     =0.6 m/s²

The average acceleration of the cyclist was 0.6 m/s².

8 0
3 years ago
What multiples for 90 and adds up to -23 ?
melamori03 [73]

Easy buddy...

_________________________________

Step (1)

I choose a number which is x

_________________________________

Step (2)

Multiplies by 90 :

90x

_________________________________

Step (3)

Adds up to -23 :

90x - 23

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

7 0
3 years ago
Solve for w in the proportion.
Svet_ta [14]

Answer:

w=40

Step-by-step explanation:

5 0
3 years ago
Answer number 4 this is due tomorrow
ikadub [295]

Answer:

The next mark should be at (3,-3)

5 0
3 years ago
Four teams A,B,C, and D compete in a tournament, and exactly one of them will win the tournament. Teams A and B have the same ch
beks73 [17]

Answer:

A= 0,2

B= 0,2

C= 0,4

D=0,2

Step-by-step explanation:

We know that only one team can win, so the sum of each probability of wining  is one

P(A)+P(B)+P(C)+P(D)=1

then we Know that the probability of Team A and B are the same, so

P(A)=P(B)

And that the  the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)

Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2

Now if we use the first formula:

P(A)+P(B)+P(C)+P(D)=1

P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1

0,5 P(A)+0.9=1

0,5 P(A)= 0,1

P(A)= 0,2

P(B)= 0,2

P(C)=0,4

P(D)=0,2

4 0
3 years ago
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