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2 years ago

(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)

Mathematics

1 answer:

RUDIKE [14]2 years ago

8 0

Answer:

7.21 units

Step-by-step explanation:

GIven data

Point 1= (8,3)

x1= 8

y1= 3

Point 2= (2,7)

x2= 2

y2= 7

The expression for the distance between two points is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((2-8)²+(7-3)²)

d=√((-6)²+(4)²)

d=√36+16

d=√52

d= 7.21

Hence the distance between the points is 7.21 units

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(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)​

(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)