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andreev551 [17]
2 years ago
12

(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)​

Mathematics
1 answer:
RUDIKE [14]2 years ago
8 0

Answer:

7.21 units

Step-by-step explanation:

GIven data

Point 1= (8,3)

x1= 8

y1= 3

Point 2=  (2,7)​

x2= 2

y2= 7

The expression for the distance between two points is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((2-8)²+(7-3)²)

d=√((-6)²+(4)²)

d=√36+16

d=√52

d= 7.21

Hence the distance between the points is 7.21 units

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12 What is the solution to this equation?
Levart [38]

Answer:

x=-5

Step-by-step explanation:

add 7 to 53 then divide -12 to itself and 60.

5 0
2 years ago
Ms.jones wants to feed each of the children she babysits a half sandwich for lunch. If she babysits 8 children, how many sandwic
insens350 [35]

Answer:

4

Step-by-step explanation:

If she makes 4 sandwiches, she splits the 4 sandwiches among 8 children. 4/8 is 1/2 which is half a sandwich for everyone.

8 0
3 years ago
If the following fraction is reduced, what will be the exponent on the p? - 5p^5q^4/8p^2q^2 5 4 3 2
SSSSS [86.1K]
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
-\cfrac{5p^5q^4}{8p^2q^2}\implies -\cfrac{5}{8}\cdot \cfrac{p^5q^4}{p^2q^2}\implies -\cfrac{5}{8}\cdot p^5p^{-2}q^4q^{-2}
\\\\\\
-\cfrac{5}{8}\cdot p^{5-2}q^{4-2}\implies -\cfrac{5\stackrel{\downarrow }{p^3}q^2}{8}
8 0
3 years ago
Read 2 more answers
A large chess tournament starts with 1024 players. How many players will be remaining after 6 rounds
docker41 [41]

Answer:

16

Step-by-step explanation:

After reach round the number of players will be reduced by a half.

After 1 round it will be 1024 * 11/2 = 512, after  2 rounds it will be 1024 * (1/2)^2 = 256 etc..

Thus, after 6 rounds  the remaining players will be 1024* (1/2)^6

=  16  (answer)

5 0
3 years ago
A real estate agent has 1212 properties that she shows. She feels that there is a 50P% chance of selling any one property during
forsale [732]

Answer:

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The probability of a property being sold is independent of any other property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

12 properties

This means that n = 12

She feels that there is a 50% chance of selling any one property during a week.

This means that p = 0.5

Compute the probability of selling no more than 6 properties in one week.

This is:

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.2256

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 + 0.1934 + 0.2256 = 0.6127

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

6 0
2 years ago
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