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2 years ago

(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)

Mathematics

1 answer:

RUDIKE [14]2 years ago

8 0

Answer:

7.21 units

Step-by-step explanation:

GIven data

Point 1= (8,3)

x1= 8

y1= 3

Point 2= (2,7)

x2= 2

y2= 7

The expression for the distance between two points is given as

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((2-8)²+(7-3)²)

d=√((-6)²+(4)²)

d=√36+16

d=√52

d= 7.21

Hence the distance between the points is 7.21 units

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2 years ago

Ms.jones wants to feed each of the children she babysits a half sandwich for lunch. If she babysits 8 children, how many sandwic

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If she makes 4 sandwiches, she splits the 4 sandwiches among 8 children. 4/8 is 1/2 which is half a sandwich for everyone.

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3 years ago

If the following fraction is reduced, what will be the exponent on the p? - 5p^5q^4/8p^2q^2 5 4 3 2

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$\bf ~~~~~~~~~~~~\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
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3 years ago

Read 2 more answers

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After reach round the number of players will be reduced by a half.

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3 years ago

A real estate agent has 1212 properties that she shows. She feels that there is a 50P% chance of selling any one property during

forsale [732]

Answer:

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The probability of a property being sold is independent of any other property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

12 properties

This means that $n = 12$

She feels that there is a 50% chance of selling any one property during a week.

This means that $p = 0.5$

Compute the probability of selling no more than 6 properties in one week.

This is:

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.2256$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 + 0.1934 + 0.2256 = 0.6127$

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

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2 years ago

(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)​

(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)