(iii) A relation between a and b such that point (a,b) isequidistant from the points (8,3) and (2,7)
1 answer:
Answer:
7.21 units
Step-by-step explanation:
GIven data
Point 1= (8,3)
x1= 8
y1= 3
Point 2= (2,7)
x2= 2
y2= 7
The expression for the distance between two points is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((2-8)²+(7-3)²)
d=√((-6)²+(4)²)
d=√36+16
d=√52
d= 7.21
Hence the distance between the points is 7.21 units
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