Answer:
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
Polynomial Long Division :
4.3 Polynomial Long Division
Dividing : x5-5x4+10x3-10x2+5x-1
("Dividend")
By : x-1 ("Divisor")
dividend x5 - 5x4 + 10x3 - 10x2 + 5x - 1
- divisor * x4 x5 - x4
remainder - 4x4 + 10x3 - 10x2 + 5x - 1
- divisor * -4x3 - 4x4 + 4x3
remainder 6x3 - 10x2 + 5x - 1
- divisor * 6x2 6x3 - 6x2
remainder - 4x2 + 5x - 1
- divisor * -4x1 - 4x2 + 4x
remainder x - 1
- divisor * x0 x - 1
remainder 0
Quotient : x4-4x3+6x2-4x+1 Remainder: 0
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Answer:
x = 12
Step-by-step explanation:
5x + 15 = 75
-15 -15
5x = 60
x = 12
Answer:
b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The mean of the uniform probability distribution is:
The standard deviation of the uniform distribution is:
The probability that we find a value X lower than x is given by the following formula.
Uniform distribution between 2.93 and 3.1 volts
This means that 
. So
Mean:
Standard deviation:
What is the probability that a battery has a voltage less than 2.98?
So the correct answer is:
b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941
