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2 years ago

11

(3p)^2 without exponents

1 answer:

g100num [7]2 years ago

3 0

Hello :
(3p)² =3²×p² = 9p²

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1404 is the surface area of 30 nameplates.

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3 years ago

6x9x(-5) what is the answer to this question?

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2 years ago

Identify the name and label the parts of the following polynomial: − 2x^4+24^2-10

lianna [129]

-2x^4 + 24x^2 - 10

u have 3 terms.....and since u are only dealing with 1 variable with the highest exponent being 4, then what u have here is a 4th degree trinomial.
U have a lead coefficient of -2.
Ur constant term is -10
And ur middle term (24x^2) has a degree of 2

a cubic binomial.....a binomial has 2 terms and it being cubic means the highest term has a degree of 3
example would be : x^3 - 4

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3x^2 + 6xy -10x^5 + y^6 - 10x^3y^5

when u have a polynomial with more then 1 variable, such as this one, the degree is not the highest exponent, it is the highest term.....-10x^3y^5...u add the exponents....so this term has a degree of 8, and it is the highest one in this problem....so this is an 8th degree polynomial with 5 terms

7 0

2 years ago

Factoring with Algebra Tiles Represent the quadratic polynomial 2x2 + x – 6 using algebra tiles and determine the equivalent fac

Nezavi [6.7K]

Answer:

Two zero pair

$f(x)=(2x-3)(x+2)$

Step-by-step explanation:

We are given the following quadratic equation:

$f(x) = 2x^2+x-6$

Since, this a quadratic equation we would have two zero pairs for this model.

Factored form of polynomial:

$f(x) = 2x^2+x-6\\f(x)=2x^2+ 4x -3x -6\\f(x)=2x(x+2)-3(x+2)\\f(x)=(2x-3)(x+2)$

is the required factored form of the given polynomial.

6 0

2 years ago

Express with radical signs instead of fractional exponents. Rationalize the denominator.

CaHeK987 [17]

$x^{\frac{1}{2}} = \sqrt[2]{x}$ and $3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}}$ so

$3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x} = \frac{\sqrt{x}}{\sqrt{3}}$

and you rationalize denominator by multiplying numerator and denominatr by $\sqrt{3}$ so that gives--

$\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}$

Your answer is $\frac{\sqrt{3x}}{3}$

5 0

2 years ago