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daser333 [38]
3 years ago
10

What is the slope of a line that passes through (3,-7) and (-1,1)?

Mathematics
2 answers:
Rudiy273 years ago
5 0

\text{The slope formula:}\ m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{We have:}\\(3;-7)\to x_1=3;\ y_1=-7\\(-1;\ 1)\to x_2=-1;\ y_2=1\\\\\text{substitute:}\\\\m=\dfrac{1-(-7)}{-1-3}=\dfrac{1+7}{-4}=\dfrac{8}{-4}=-2

Answer: m = -2

nikdorinn [45]3 years ago
5 0

Slope = (y2 - y1)/(x2 - x1)

= (1 + 7)/(-1 - 3)

= 8/-4

= -2

Answer

slope = -2

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3 years ago
(x-3)(x-8)=0 apply the zero product property
SashulF [63]

Answer:

x=3

x=8

Step-by-step explanation:

The "Zero Product Property" says:

If  (x−3)(x−8) = 0  then   (x−3) = 0   or   (x−8) = 0

Now we just solve each of those:

For (x−3) = 0 we get x = 3

For (x−8) = 0 we get x = 8

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8 0
3 years ago
HELP ME PLEASE ASAP!​
Viktor [21]

Answer:

second option

Step-by-step explanation:

Pythagoras for right-angled triangles :

c² = a² + b²

c is the Hypotenuse, the line opposite of the 90 degree angle.

a and b are the other 2 sides.

the distance between 2 points is the Hypotenuse of a right-angled triangle of the coordinate differences in x and y.

so, we have (-2, -3) and (3, 2)

distance² = (x1 - x2)² + (y1 - y2)² = (-2 - 3)² + (-3 - 2)² =

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3 years ago
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