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ziro4ka [17]
2 years ago
10

Please help Thank you

Mathematics
1 answer:
Tanzania [10]2 years ago
6 0
     3(t + 5) = 12
3(t) + 3(5) = 12
     3t + 15 = 12
          - 15  - 15
             3t = -3
              3     3
               t = -1

    -(c - 8) = 0
-(c) - (-8) = 0
     -c + 8 = 0
          - 8  - 8
           -c = -8
           -1    -1
            c = 8

      -10(s + 3) = 9
-10(s) - 10(3) = 9
       -10s - 30 = 9
              + 30 + 30
               -10s = 39
                -10    -10
                    s = -3.9

     2(f - 7) = 2
2(f) - 2(7) = 2
    2f - 14 = 2
       + 14 + 14
           2f = 16
           2      2
             f = 8

    -7(2t + 5) = -21
-7(2t) - 7(5) = -21
     -14t - 35 = -21
           + 35   + 35
            -14t = 14
            -14    -14
                t = -1

        1²/₃(3w + 10) = 0
1²/₃(3w) + 1²/₃(10) = 0
            5w + 16²/₃ = 0
                   - 16²/₃ - 16²/₃
                       5w = -16²/₃
                        5        5
                         w = -3¹/₃

     ⁵/₉(°F - 32) = °C
     ⁵/₉(°F - 32) = 8
⁵/₉(°F) - ⁵/₉(32) = 8
     ⁵/₉°F - 17⁷/₉ = 8
            + 17⁷/₉ + 17⁷/₉
               ⁵/₉°F = 25⁷/₉
        1⁴/₅(⁵/₉°F) = 1⁴/₅(25⁷/₉)
                  °F = 46²/₅
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Answer:

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Step-by-step explanation:

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in this case, the formula can be applied in the following way

a^2 = b^2  + c^2  - 2*b*c*cos(α)

Where

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(See attached picture)

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3/(x + 4) = (x + 2)/5

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5 × 3/(x + 4) = 5 × (x + 2)/5

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(x + 4) × 15/(x + 4) = (x + 4) × (x + 2)

Provided that x + 4 ≠ 0, we can cancel the factors of x + 4 on the left side:

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Move everything to one side:

0 = x² + 6x - 7

We can factorize easily in this case
0 = (x + 7) (x - 1)

Then

x + 7 = 0   or   x - 1 = 0

⇒   x = -7   or   x = 1

7 0
2 years ago
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