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3 years ago

Please help Thank you

Mathematics

1 answer:

Tanzania [10]3 years ago

6 0

3(t + 5) = 12
3(t) + 3(5) = 12
3t + 15 = 12
- 15 - 15
3t = -3
  3 3
t = -1

  -(c - 8) = 0
-(c) - (-8) = 0
-c + 8 = 0
- 8 - 8
-c = -8
-1 -1
c = 8

  -10(s + 3) = 9
-10(s) - 10(3) = 9
-10s - 30 = 9
  + 30 + 30
-10s = 39
-10 -10
  s = -3.9

2(f - 7) = 2
2(f) - 2(7) = 2
  2f - 14 = 2
+ 14 + 14
2f = 16
2 2
f = 8

  -7(2t + 5) = -21
-7(2t) - 7(5) = -21
-14t - 35 = -21
+ 35 + 35
-14t = 14
-14 -14
t = -1

  1²/₃(3w + 10) = 0
1²/₃(3w) + 1²/₃(10) = 0
  5w + 16²/₃ = 0
- 16²/₃ - 16²/₃
5w = -16²/₃
5 5
w = -3¹/₃

⁵/₉(°F - 32) = °C
⁵/₉(°F - 32) = 8
⁵/₉(°F) - ⁵/₉(32) = 8
⁵/₉°F - 17⁷/₉ = 8
+ 17⁷/₉ + 17⁷/₉
⁵/₉°F = 25⁷/₉
  1⁴/₅(⁵/₉°F) = 1⁴/₅(25⁷/₉)
  °F = 46²/₅

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Given:

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Let the first number be 'x', the second number be 'y' and the third number be 'z'

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