<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
10 feet length and 6 feet width.
Step-by-step explanation:
If the total area of the patio is going to be equal to 60 square feet and the length is going to be 4 feet longer than the width, the dimensions that she should use for the patio are 10 feet for the length and 6 feet for the width which will equal to 60 square feet in total.
I hope this answer helps.
16-4=12
12x5=60
I'm putting together assumptions as this isn't really clear to me, I apologize.
Think of it as a normal linear equation first. Let's find the slope.
m = rise/run = (3-1)/(0-1) = -2
We know the slope is negative now, so we can immediately get rid of the first two answers. Now, we know that the solutions must be under the line itself, so we can try figuring it out by testing some points. Let's use (0,0).
Is 0 </> 0+3? Since it's <, then we know the last answer is correct (y < -2x + 3).
Answer:
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