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Talja [164]
4 years ago
9

The graph of a polynomial of degree 7 has five x-intercepts, all with multiplicity 1. Describe the nature and number of all its

zeros
A. The function has 7 real zeros
B. The function has 5 read zeros.
C. The function has 5 real zeros and 2 complex zeros
D. The function has 2 real zeros and 5 complex zeros.
Mathematics
1 answer:
Marysya12 [62]4 years ago
5 0
Do you know that multiplicity means the number of times any factor appears in the factored result? Just checking. For example The graph of y = x^2 - 2x + 1 has a multiplicity of 2. they are y = (x - 1) * ( x - 1)

y = x^2 - 3x - 4 has 2 factors.
y = (x - 4)(x + 1) each of the factors has a multiplicity of 1. 

So the answer to your question is there are 5 real zeros and 2 complex zeros. 
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Is 5/4 greater than , less than , or equal to the square root of 2
victus00 [196]

Answer:

less than

Step-by-step explanation:

the square root of 2 is 4 and 5/4 is 1.25

8 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
GrogVix [38]

Answer:

<u>1. Type of function</u>: absolute value function

<u>2. The three transformations from the parent function f(x) = |x| are</u>:

  • Translation 3 units to the left
  • Vertical stretch with a scale factor of 2
  • Translation 5 units downward

Explanation:

<u>1. Type of function</u>

The parent function |x| is the absolute value function. It returns the positive value of the argument (x).

Thus the function f(x) = 2|x + 3| - 5 is also an absolute value function.

It returns the positive value of x + 3, then multiplyes it by 2, and finally subtract 5.

This is a piecewise function.

For the values of x ≥ - 3, the output is 2(x +3) - 5 = 2x + 6 - 5 = 2x + 1.

For the values of x < - 3, the output is 2 (-x - 3) - 5 = -2x - 6 - 5 = -2x - 11.

The vertex of this function is at x = - 3: 2 (- 3 + 3) - 5 = 2(0) - 5 = 0 - 5 = 5.

Thus the vertex is (-3, 5).

<u>2. Transformations from the parent function f(x) = |x|</u>.

When you know the parent function and the daughter function you can know the transformations done of the former to get the later by some simple rules.

a)<u> Translation in the horizontal direction</u>.

When you add a positive value to the argument the function is translated to the left.

Thus, when you add 3 to x, |x| becomes |x + 3| and it is a translation 3 units to the left.

b) <u>Vertical stretch</u>

When you multiply the argument by a constant, the function stretches vertically.

Thus, when you multiply |x + 3| by 2, to get 2|x + 3|, the function is vertically stretched by a scale factor of 2.

c) <u>Vertical translation</u>

When you subtract a constant value from the function, you translate it downward.

Thus, when you subtract 5 from 2|x + 3| - 5, you translate the function 5 units downward.

6 0
3 years ago
HELP ASAP WITH THIS QUESTION
alexgriva [62]
Hey there (again)

x = 2y  \\ y = -2  \\ x = 2(-2) \\x= -4 \\ \\ \\ w + xy + 4x^2  = 2\\ w+-4(-2) + 3(-4)^2 = 2 \\ w + 8 + 3(16) = 2 \\ w + 8 + 48 = 2 \\ Subtract56: w + 56 =2 \\ 56 - 56 (Cancel) \\ 2 - 56 = -54 \\ w = -54

Answer: B  the simplification performed in step 2 is invalid or incorrect

Good luck on your assignment and enjoy your day 

~MeIsKaitlyn:)
5 0
3 years ago
98 POINTS!<br> d(e-f)=g<br> Solve For f.
Lubov Fominskaja [6]

d (e - f) = g

de - df = g

df = de - g

f = ed - g/d

Hope helps-Aparri

5 0
3 years ago
Read 2 more answers
Help with this question
wlad13 [49]
<h3>A.</h3>

See below for a graph

<h3>B.</h3>

The inverse of a function appears on a graph as the reflection of the function across the line y=x. This is because the inverse relation is effectively the same relation with the variables x and y swapped. Here, the graphs of f(x) and g(x) are mirror images of each other across the line y=x, so we can see they are inverse functions.

The same technology allows us to graph y=f(g(x)) and y=g(f(x)). Both are graphs of y=x, as expected.

7 0
3 years ago
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