The answer is (C) because you multiply each point by 1.5.
A quadratic equation is set up in the form of ax² + bx +c
First set equation = to 0
0= x² - 5x - 24
Next plug into quadratic formula( -b Plus or minus the √b²-4ac) ÷ 2a
[10 plus or minus √(25² - 4×1×24)] ÷ 2
Solve for inner parenthesis first
√625- 96 = √529
Now set up two equations
(10 + √529) ÷2 = x = 16.5
(10 - √529) ÷2 = x = -6.5
So therefore x = 16.5 and -6.5
You are asking for the condition needed for the
<span>two segments to be perpendicular to each other. </span>
<span>If the slope of one segment is m, then the slope of a perpendicular segment would be -1/m </span>
<span>this means that m2 = -1/m and so m2 x m = -1 </span>
<span>If you look carefully at your choices, the 3rd answer involves the two slope and has the -1. It's </span>
<span>the correct answer.</span>
Answer:
2 x 2 x 7 = 28 2 x 2 x 2 x 5 = 40 2 x 2 x 2 x 2 x 3 x 3 = 144 2 x 2 x 2 x 2 x 3 x 3 x 5 x 7 = 504... ... The LCM of the given two numbers using prime factorization is 36 ...
Step-by-step explanation:
Answer:
The water level is dropping at a rate of 0.24 ft/s
Step-by-step explanation:
Here, we simply want to calculate the change in depth (height of the cone) , given the volume change
Mathematically, we have the volume of a cone as;
V = 1/3 * π * r^2 * h
we are given dv/dt as 12 ft^3/m
dv/dh = 1/3 * π * r^2
Substituting the value for the radius, we have
dv/dh = 1/3 * 22/7 * 4^2 = 50.29
dh/dt = dh/dv * dv/dt
dh/dv = 1/(dv/dh) = 1/50.29
Thus,
dh/dt = 1/50.29 * 12
dh/dt = 0.24 ft/s
