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zzz [600]
3 years ago
13

. If x tan 45° sin 30° = cos 30° tan 30°, then x is equal

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0

Answer:

x = \frac{\sqrt{3} }{3}

Step-by-step explanation:

You can either use the unit circle to find your values and then solve for x or plug it into the calc directly to find your answer (don't forget to put your mode on deg!). It is much faster to plug it into your calc. Simply just divide both sides by tan45°cos30° and you should isolate x and find your answer.

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Select the correct answer.
Gre4nikov [31]

Answer:The value of the function approaches as x approaches or 6

Step-by-step explanation: , and the value of the function approaches as x approaches . Which function could be function f

3 0
2 years ago
Jimmy has a window frame in his house. The window measures to have a width of 36 inches and a height of 48 inches. What is the d
Olenka [21]

Answer:

B.60 inches

Step-by-step explanation:

you know you can consider two triangles because of the diagonal cut. and the distance wound be √(36²+48²)=60 inches

4 0
2 years ago
help please!! thank you! will give BRAINLIEST!! *graphs, and just answer question b. and c.! thank youuuu
svlad2 [7]

Answer:

B and C

Step-by-step explanation:

7 0
2 years ago
Which is an example of continuous data?
Lynna [10]

Answer:

A) amount of snowfall in a blizzard  

Step-by-step explanation:

Both continuous and discrete data are quantitative.

The difference is that  

  • Continuous data can take any value. You obtain it by measurement.
  • Discrete data can take only certain values. You obtain it by counting.

The amount of snowfall in a blizzard is continuous data.  It can take any value such as 100.3 cm or 250.5 cm .

B) is wrong. The number of students who pass a math quiz is discrete data. You can't have half a student.

C is wrong. The number of languages an individual speaks is discrete data. You can't speak half a language.  

D) is wrong. The number or treadmills in a gym is discrete data. You can't have half a treadmill.

7 0
3 years ago
Read 2 more answers
The constraint for the potential plant site 2 can be written as:
sdas [7]

Answer:

c. x21 + x22 + x23 less or equal than 2800 y2

Step-by-step explanation:

The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.

4 0
3 years ago
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