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tatiyna
4 years ago
5

A steel cargo container is shaped like a cube measuring 5.2 ft on each edge how much steel is needed to make this container? Sho

w your work.
Mathematics
1 answer:
bearhunter [10]4 years ago
6 0

Answer:

162.24 ft

Step-by-step explanation:

So you first find the area of one side.

5.2 x 5.2 = 27.4

Then you times it by 6, because a cube has 6 sides.

27.4 x 6 = 162.24 ft

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There are 407 students who are enrolled in an introductory Chinese course if there are five boys to every 6 girls how many boys
Mrac [35]

Answer:

6x+5x=407

11x=407

x=37

boys

Step-by-step explanation:

7 0
3 years ago
What is 2 3/8 * 1/3. Estimate the product
stealth61 [152]
2 3/8 x 1/3 I believe? First you need to change 2 into a 16 then add that into 3 which is 19/8. You multiply across with 1/3 like with numerator with numerator and denominator with denominator. That then equals:19/24. You can't estimate it because 19 is a prime number.
7 0
3 years ago
Evaluate each expression for g = -7 and h = 3 and match it to its value.
Molodets [167]

The given expressions are solved and matched

<h3><u>Solution:</u></h3>

To match the given expressions we need to solve the expressions with the given values of g and h and find their value.

Given that g = -7 and h = 3

\begin{array}{l}{\text { 1) } g+h=-7+3=-4} \\\\ {\text { 2) } g-h=-7-3=-10} \\\\ {\text { 3) } h-g=3+7=10} \\\\ {\text { 4) } g h=-7 \times 3=-21} \\\\ {\text { 5) } g+h^{2}=-7+3^{2}=-7+9=2} \\\\ {\text { 6) } g^{2}-h=(-7)^{2}-3=49-3=46}\end{array}

3 0
3 years ago
Of every 300 magic cakes Farah makes, 90 are chocolate, what percentage of chocolate cakes Farah makes?
navik [9.2K]

Answer:

Total magic cakes =300

chocolate cakes =90

so if you want the percentage of chocolate you will divide the number of chocolate cakes over the total number of chocolates

% of chocolate cakes = 90/300×100%

=30%

5 0
3 years ago
Please help! :) Need answer fast!
Vlada [557]

Answer:

x = 3

y = 2

Step-by-step explanation:

When 2 triangles are congruent, they will have exact same 3 sides length and exact same 3 angles measure.

So we can say:

-2x + 6y = 6

and

-7x + 8y = -5

Let's multiply first equation by 7 and 2nd equation by -2, to get:

7 [-2x + 6y = 6] = -14x +42y = 42

and

-2 [-7x + 8y = -5] = 14x - 16y = 10

Now adding these 2 new equations and solving for y:

-14x +42y = 42

14x - 16y = 10

----------------------

26y = 52

y = 52/26

y = 2

Now we put y = 2 into 1st equation (or any other) and solve for x:

-2x + 6y = 6

-2x + 6(2) = 6

-2x + 12 = 6

6 = 2x

x = 6/2

x = 3

5 0
3 years ago
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