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tatiyna
3 years ago
5

A steel cargo container is shaped like a cube measuring 5.2 ft on each edge how much steel is needed to make this container? Sho

w your work.
Mathematics
1 answer:
bearhunter [10]3 years ago
6 0

Answer:

162.24 ft

Step-by-step explanation:

So you first find the area of one side.

5.2 x 5.2 = 27.4

Then you times it by 6, because a cube has 6 sides.

27.4 x 6 = 162.24 ft

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A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel
Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

x_{Sh} = x_{o} + v_{Sh}\cdot t

Submarine

x_{Su} = x_{o}+v_{Su}\cdot t

Where:

x_{o} - Position of Diego Garcia island, measured in miles.

x_{Sh}, x_{Su} - Current positions of ship and submarine, measured in miles.

v_{Sh}, v_{Su} - Velocities of ship and submarine, measured in miles per hour.

t - TIme, measured in hours.

If we know that x_{Sh} - x_{Su} = 241\,mi, v_{Sh} = 19\,\frac{mi}{h} and t = 7\,h, then:

x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t

We clear now the velocity of submarine:

\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}

v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}

v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}

v_{Su} = -15.429\,\frac{mi}{h}

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0
3 years ago
615.44 rounded to the nearest tenth
Whitepunk [10]
The answer is 615.4

Hope this helps :)
5 0
3 years ago
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