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3 years ago

Solve for n -3n-5=16

Mathematics

2 answers:

Nataly [62]3 years ago

8 0

Answer:

n = -7

Step-by-step explanation:

Add 5 to each side, so it now looks like this: -3n = 21
Divide each side by -3 to cancel out the -3 next to n. It should now look like this: n = -7

I hope this helps!

Nezavi [6.7K]3 years ago

7 0

Answer:

n = -7

Step-by-step explanation:

Solve for n:

-3 n - 5 = 16

Hint: | Isolate terms with n to the left-hand side.

Add 5 to both sides:

(5 - 5) - 3 n = 5 + 16

Hint: | Look for the difference of two identical terms.

5 - 5 = 0:

-3 n = 16 + 5

Hint: | Evaluate 16 + 5.

16 + 5 = 21:

-3 n = 21

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -3 n = 21 by -3:

(-3 n)/(-3) = 21/(-3)

Hint: | Any nonzero number divided by itself is one.

(-3)/(-3) = 1:

n = 21/(-3)

Hint: | Reduce 21/(-3) to lowest terms. Start by finding the GCD of 21 and -3.

The gcd of 21 and -3 is 3, so 21/(-3) = (3×7)/(3 (-1)) = 3/3×7/(-1) = 7/(-1):

n = 7/(-1)

Hint: | Simplify the sign of 7/(-1).

Multiply numerator and denominator of 7/(-1) by -1:

Answer: n = -7

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Where:

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Let's start calculating the mean value:

$\bar {x}=\frac{1}{N} \sum_{i=1}^{N}x_{i}$

$\bar {x}=\frac{1}{15}*(180+1600+90+140+50+260+400+90+380+110+10+60+20+340+80)$

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Now, let's calculate the summation:

$\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=(180-254)^2+(1600-254)^2+(90-254)^2+...+(80-254)^2$

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So, now we can calculate the standart deviation:

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Step-by-step explanation:

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3 years ago

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Lynna [10]

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Step-by-step explanation:

Step 1:

Let the sequence given here is -5, -7, -9, -11, -13 ......

Here the first term (a₁) of sequence is -5

And the common difference between the numbers in the sequence is

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Step 2;

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