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Kazeer [188]
3 years ago
14

Write 2.9687 in p/q form , where p and q are integers and q is non zero

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

Step-by-step explanation:

2.9687=\frac{29687}{10000}

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Gertrude started an experiment with 15 gummy bears. After 6 days, there were 1,523 gummy bears. Write an exponential function th
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9514 1404 393

Answer:

  y = 15·2.1599^x

Step-by-step explanation:

We know that the number changed by the ratio 1523/15 = 101.5333... in 6 days, so the daily multiplier is the 6th root of this:

  b = 101.5333...^(1/6) = 2.1599 . . . rounded to 4 dp

Of course, the coefficient 'a' in the equation is the initial number, 15.

Your exponential equation is ...

  y = 15·2.1599^x

  a = 15

  b = 2.1599

5 0
3 years ago
Trevor is analyzing a circle, y2 + x2 = 49, and a linear function g(x). Will they intersect?
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We have a circumference that is given by the following equation:

x^{2}+y^{2}=49

We can write this equation in its standard form as follows:

 x^{2}+y^{2}=7^{2} \\ where \ the \ radius \ r=7

On the other hand, the linear function is given as the following table:

x \ \ \ \ \ \ \ \ g(x) \\ -1 \ \ -9.2 \\ 0 \ \ \ \ \ -9 \\ 1 \ \ \ \ \ -8.8

To check if the circle and the line intersects, let's substitute the equation of the line into the equation of the circle to see if there is a real solution, so:

x^{2}+(0.2x-9)^{2}=49 \\ \\ \therefore x^{2}+0.04x^{2}-3.6x+81=49 \\ \\ \therefore 1.04x^{2}-36x+32=0 \\ \\ Solving \ for \ x: \\ x_{1}=33.70 \\ x_{2}=0.91 \\ \\ Solving \ for \ y: \\ y_{1}=0.2(33.70)-9=-2.26 \\ y_{2}=0.2(0.91)-9=-8.18

 Finally the intersects are:

 P_{1}(33.70, -2.26) \ and \ P_{2}(0.91, -8.18)
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2 years ago
Read 2 more answers
1. consider a lottery with three possible outcomes: $125 will be received with probability 0.25, $100 will be received with prob
tigry1 [53]

The lottery's anticipated worth is $80.

Given that,

The probability of receiving $125 is 0.25; the likelihood of receiving $100 is 0.3; and the likelihood of receiving $50 is 0.45.

A) EV=125*.2+100*.3+50*.5=$80

The lottery's anticipated worth is $80.

The expected value is obtained by multiplying each result by its likelihood.

The expected value of the lottery is then calculated by adding up all of these.

This is what we have: ;;

125(0.2) + 100(0.3) + 50(0.5) (0.5)

= 25 + 30 + 25 = $80

B) This is the formula for variance is shown in figure :

So, we can calculate the variance as follows:

.2*(125-80)^2+.3*(100-80)^2+.5*(50-80)^2=975

C) A risk-neutral person would pay $80 or less to play the lottery.

To learn more about probability click here:

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1 year ago
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Draw a tree diagram to represent the following scenario. You choose a random letter from the word SANDWICH. How many possible ou
VARVARA [1.3K]

Probability helps us to know the chances of an event occurring. There are 8 different scenarios possible.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}

For the given word SANDWICH, there are 8 different scenarios possible, which can be represented as shown below.

Hence, there are 8 different scenarios possible.

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8 0
1 year ago
find the magnitude of two forces f1 and f2 such that at right-angle to each other, their resultant is √13N. Also, if the two for
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This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.

Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6

Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2

The magnitudes of the two forces are 2N and 3N, in no particular order.

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3 years ago
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