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3 years ago

14

Write 2.9687 in p/q form , where p and q are integers and q is non zero

1 answer:

Anna35 [415]3 years ago

4 0

Answer:

Step-by-step explanation:

2.9687= $\frac{29687}{10000}$

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Refer to the accompanying TI-83/84 Plus calculator display of a 95% confidence interval. The sample display results from using a

nikklg [1K]

Answer:

The confidence interval is $22.805$

Step-by-step explanation:

We have given,

The Z interval (23.305,25.075)

Mean $\bar{x}=23.69$

Sample n=30

To find : The confidence interval?

Solution :

We know, The confidence interval is in the format of

$\bar{x}-E$

E denotes the margin of error,

$E=\frac{U-L}{2}$

Where, U is the upper limit U=25.075

L is the lower limit L=23.305

$E=\frac{25.075-23.305}{2}$

$E=\frac{1.77}{2}$

$E=0.885$

Substitute the value of E and $\bar{x}$ in the formula,

$23.69-0.885$

$22.805$

Therefore, The confidence interval is $22.805$

8 0

4 years ago

Can somone give me the answer to 2 x 0

marshall27 [118]

Any number times 0 is going to equal 0

8 0

3 years ago

Read 2 more answers

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by

11111nata11111 [884]

Answer:

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is $V=l\times b\times h$

$V=(11-2x)\times (7-2x)\times x$

$V=4x^3-36x^2+77x$

Derivate w.r.t x,

$V'(x)=4(3x^2)-2(36x)+77$

$V'(x)=12x^2-72x+77$

The critical point when V'(x)=0

$12x^2-72x+77=0$

Solve by quadratic formula,

$x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}$

$x=4.607,1.392$

Derivate again w.r.t x,

$V''(x)=24x-72$

Now, $V''(4.607)=24(4.607)-72=38.568>0$ (+ve)

$V''(1.392)=24(1.392)-72=-38.592$ (-ve)

So, there is maximum at x=1.392.

The length of the box is $l=11-2x$

$l=11-2(1.392)=8.216$

The breadth of the box is $b=7-2x$

$b=7-2(1.392)=4.216$

The height of the box is h=1.392.

The dimension of the open rectangular box is $8.216\times 4.216\times 1.392$ .

The volume of the box is $V=l\times b\times h$

$V=8.216\times 4.216\times 1.392$

$V=48.217\ in.^3$

The volume of the box is 8.217 cubic inches.

5 0

3 years ago

Sam had his highest scoring basketball game by making 18 shots for a total of 43 points. If all of his points came from 2- and 3

sweet-ann [11.9K]

43 - 18*2 = 43 -36 = 7

7 were 3 point shots
11 were 2 point shots

8 0

3 years ago

Approximately how many diameters does it take to equal the measure of a circle's circumference?

padilas [110]

Its C. dhadhkcd,bdv,bsvbhbsvbdv,dbv,d,vdhv,bd

6 0

3 years ago