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den301095 [7]
3 years ago
5

Line passing through (0, 9) , (8, 7)

Mathematics
1 answer:
Aneli [31]3 years ago
5 0

<u>We are given:</u>

The 2 points through which the line passes through

(0,9) and (8,7)

__________________________________________________________

<u>Finding the equation of the line:</u>

To find the equation of the line, we will use the slope-intercept form:

y = mx + b           [where m is the slope and b is the y-intercept]

So, we need the slope and the y-intercept of the line in order to find the equation

<u>Finding the slope:</u>

We know that the slope of a line is:  change in y / change in x

So, Slope = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}

replacing the variables:

Slope = (7-9) / (8-0)

Slope =  -2 / 8

Slope = -1/4

<u>Finding the y-intercept:</u>

Since we know the slope, we know that the equation of the line will look like:

y=  (-1/4)x + b              [where b is the y-intercept]

we know that the ordered pair (0,9) will satisfy the equation since the line passes through that point

So, y = 9 and x = 0 will satisfy the equation:

9 = (-1/4)(0) + b

b = 9

Hence, the y-intercept is 9

<u>Equation of the line:</u>

We know that the general form of the slope-intercept form is:

y = mx + b                [where m is the slope and b is the y-intercept]

Since we know the values of the slope and the y-intercept:

y = (-1/4)x + 9

y = -x/4 + 9 is the equation of the line that passes through the given points

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What is the slope of the line that passes through the points (1, 1) and (4, 4)?
gizmo_the_mogwai [7]

Answer:

The answer is 1

Step-by-step explanation:

Formula for finding the slope: \frac{y2-y1}{x2-x1}

Take y2 and y1 from (4,<u>4</u>) (1,<u>1</u>)

Take x2 and x1 from (<u>4</u>,4) (<u>1</u>,1)

\frac{y2-y1}{x2-x1}  = \frac{4-1}{4-1} = \frac{3}{3} = 1

This is how the answer is 1

Hope it helps :)

8 0
2 years ago
a chef uses 4 3/4 cups of broth for 10 servings of soup.how much broth is is one serving . let x represent amount. 4 3/4/10 =x/1
enyata [817]
Let's firstly convert the mixed fraction to "improper" and then proceed,

\bf \begin{array}{ccll}&#10;\stackrel{broth}{cups}&servings\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;4\frac{3}{4}&10\\\\&#10;x&1&#10;\end{array}\implies \cfrac{\quad \stackrel{mixed}{4\frac{3}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{4\cdot 4+3}{4}\quad }{x}=\cfrac{10}{1}

\bf \cfrac{\quad \stackrel{improper}{\frac{19}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{19}{4}\quad }{\frac{x}{1}}=\cfrac{10}{1}\implies \cfrac{19}{4}\cdot \cfrac{1}{x}=\cfrac{10}{1}\implies \cfrac{19}{4x}=\cfrac{10}{1}&#10;\\\\\\&#10;19=40x\implies \cfrac{19}{40}=x
6 0
3 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)
Bess [88]

Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

<u><em>5*[∫x^{2}dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>

<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

4 0
3 years ago
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