There are 5 couples are sitting in the row
<h3>How many couples are sitting in the row?.</h3>
The given parameters are
Maximum = 6 couples
In the hall, we have the following arrangements
<u>First couple</u>
Right = 2 couples
Left = 1 couple
<u>Another couple</u>
Left = 3 couple
Right = 1 couples
The left of the other couple is the right of the first couple
So, we have the following arrangements:
<u>First couple (1)</u>
Right = 2 couples
Left = 1 couple
<u>Another couple</u>
Right = 1 couples
The total number of couples is
Total = 1 + 2 + 1 + 1
Evaluate the sum
Total = 5
Hence, there are 5 couples are sitting in the row
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Answer:
Option A.
Step-by-step explanation:
Let M be the milk per gallon.
C be the cookies per dozen.
B be the bundle (one gallon of milk and a dozen cookies ).
Milk can be sold by itself for a profit of $1.50 per gallon. Cookies can likewise be sold at a profit of $2.50 per dozen and bundle is sold for a profit of $3.00 per bundle.
We need to maximize the profits. So, our objective function is
Therefore, the correct option is A.
There is a formula for that;
Total time = (Worker 1 * Worker 2) / (Worker 1 + Worker 2)
Total time = (80 * 120) / (80 + 120)
Total time = 9,600 / 200
Total time = 48 minutes
1. write the division as a fraction
9+n/2>16 → 9+1/2n>16
2. multiply both sides of the inequality by 2
2x9+2x1/2n>2x16
3. multiply the numbers and reduce the numbers with greatest common divisor 2 (remove number 2, the common factor from equation)
18+n>32
4. move constant to the right by adding its opposite to both sides
18+n-18>32-18
5. eliminate the opposites
n>32-18
6. subtract the numbers
n>14
hope this helped!
