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nirvana33 [79]
4 years ago
10

During a race, Bernie ran 9meters every 4 seconds, while Wendel ran 2 meters every second and got a 9-meter head start. If the r

ace was 70 meters long, did Bernie ever catch up with Wendel? If so, when? Justify your answer.
Mathematics
1 answer:
sdas [7]4 years ago
3 0

Answer:

Step-by-step explanation:

No, because Bernie had to run 9 meters 7.77777778 time (70/9) and each of those 9-meter sections took 4 seconds, so her time was 31.1111111 (7.77777778*4). While Wendel had to run 61 meters 70-his headstart (9 meters) (70-9). So he only had to run 30.5 blocks of 2 meters (61/2). And since they're only 1 second long, it's 30.5*1=30.5.

So the answer is a NO because (Bernie) 31.1111111 seconds > 30.5 seconds (Wendel).

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Airida [17]
Total number of coins in question = 275
Number of quarters among the total coins = 120
Then
Remaining number of coins = 275 - 120
                                              = 155
Percentage of coins that are nickel = 20%
Then
Number of coins that are nickel = (20/100) * 155
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                                                   = 31
Remaining number of coins = 155 - 31
                                              = 124
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Let us assume the common ratio to be = x
Then
x + 3x = 124
4x = 124
x = 124/4
   = 31
So
The number of pennies = 3 * 31
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