X=20, or x=23,or x= 16
x could equal anything 15 or higher
I am assuming the both cylinders have the same measure of radius. They only differ in height.
Larger Cylinder = 343 ft³
Smaller Cylinder = 125 ft³ ; height = 5 ft.
We can use proportion for this problem; a:b = c:d where ad = bc
5 ft :125 ft³ = x : 343ft³
5 ft * 343 ft³ = 125 ft³ * x
1715 ft⁴ = 125 ft³ * x
1715 ft⁴ ÷ 125 ft³ = x
13.72 ft = x height of the larger cylinder.
Cone S = 768pi cm³
Cone T = 6144pi cm³ ; height = 24 cm
24 cm : 6144 cm³ = x : 768 cm³
24 cm * 768 cm³ = 6144 cm³ * x
18,432 cm⁴ = 6144 cm³ * x
18,432 cm⁴ ÷ 6,144 cm³ = x
3 cm = x height of Cone S.
You need to find a number that can go into both 3 and 12. 3 can go into 3 and 12. So, you would then find out, how many times does 3 go into this number? Well, 3 goes into 3 once of course, and 3 goes into 12 four times. (3 x 4 = 12) In a fraction, this would be 1/4. (1/4 is the simplification of 3/12)
40 prizes were dolls : divide 64 by 8 and you get 8. then multiply 8 by 5 and get 40
Answer: D, D, D, D
Step-by-step explanation: Bro, it's literally all just D
