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il63 [147K]
3 years ago
13

The temperature at any random location in a kiln used for manufacturing bricks is normally distributed with a mean of 1000°f and

a standard deviation of 50°f. when glazed bricks are put in the oven, if the temperature is below 900°f, they will discolor. if the bricks are placed randomly throughout the kiln, what percentage of glazed bricks will discolor?
Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Solution: We are given:

Temperature at any random location in a kiln used for manufacturing bricks is normally distributed with mean \mu=1000, standard deviation \sigma =50

We have to find the percentage of glazed bricks that will discolor. A brick will discolor if the temperature is below 900°f.

Therefore, we have to find P(x

Using the z score formula, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{900-1000}{50}

        =\frac{-100}{50}=-2

Now we have to find P(z

Using the standard normal table, we have:

P(z

                  =2.28\%

Therefore, 2.28% of glazed bricks will discolor.

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pishuonlain [190]

Answer:

38

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Reason: Given.

Second given statement :

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Reason: Angle addition theorem.

<em>Note: < ABC is the sum of angles <DBC and  <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and  <ABD is always greater than <RST.</em>

Also,  <ABC is greater than <DBC.

Therefore, correct option for third statement is :

<h3><ABC  >  <DBC.</h3>
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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