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3 years ago

Create an equation that matches this table

Mathematics

1 answer:

Radda [10]3 years ago

6 0

The equation that matches the given table is

y = 10x + 40

Solution:

General equation of a line : y = mx + c

Let us find the equation of the table.

<u>Common differences of X: </u>

0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1

<u>Common differences of Y: </u>

50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10

$$m=\frac{\Delta y}{\Delta x}$

$$m=\frac{10}{1}$

m = 10

Substitute m = 10 in general equation of a line

y = 10x + c

To find the constant term, substitute x = 0 and y = 40.

40 = 10(0) + c

40 = 0 + c

40 = c

c = 40

Therefore the equation of a line is y = 10x + 40.

Hence the equation that matches the given table is y = 10x + 40.

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Show that the set of points that are twice as far from the origin as they are from (2, 2, 2) is a sphere. Find the center and ra

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Answer:

This is a sphere with a center $(\dfrac{8}{3},\dfrac{8}{3},\dfrac{8}{3} )$ and radius $\dfrac{4 \sqrt{3}}{3}$

Step-by-step explanation:

Given that: (x,y,z)

where;

d₁ is the distance from the origin = $\sqrt{x^2+y^2+z^2}$

d₂ is the distance from (2,2,2) = $\sqrt{(x-2)^2+(y-2)^2+(z-2)^2}$

Also;

d₁ = 2d₂

$\sqrt{x^2 + y^2 +z^2 } = 2 \sqrt{(x-2)^2 +(y-z)^2+(z-2)^2}$

By squaring both sides;

$x^2 + y^2 +z^2 = 2^2((x-2)^2 +(y-z)^2+(z-2)^2)$

$x^2 + y^2 +z^2 = 4(x-2)^2 +4(y-z)^2+4(z-2)^2$

$x^2 + y^2 +z^2 =4(x^2 -2x -2x +4) + 4(y^2 -2y -2y +4) + 4(z^2 -2z-2z+4)$

$x^2 + y^2 +z^2 =4x^2 -16x +16 + 4y^2 -16y +16 + 4z^2 -16z+16$

Collect the like terms:

$0 = 4x^2 -x^2 -16x +16 + 4y^2 -y^2 -16y +16 +4z^2 -z^2 -16z +16$

$0 = 3x^2 -16x +16 + 3y^2 -16y +16 +3z^2 -16z +16$

Divide both sides by 3

$\dfrac{0}{3} = \dfrac{3x^2 -16x +16}{3} + \dfrac{3y^2 -16y +16 }{3} + \dfrac{ +3z^2 -16z +16}{3}$

$0 = {x^2 - \dfrac{16x}{3} +\dfrac{16}{3} + {y^2 - \dfrac{16y}{3} +\dfrac{16}{3}+{z^2 - \dfrac{16z}{3} +\dfrac{16}{3}$

Using the completing the square method;

$3(\dfrac{160}{9}) -16 = {x^2 - \dfrac{16x}{3} +\dfrac{160}{9} + {y^2 - \dfrac{16y}{3} +\dfrac{160}{9}+{z^2 - \dfrac{16z}{3} +\dfrac{160}{9}$

$\dfrac{16}{3}= (x - \dfrac{8}{3})^2+ (y - \dfrac{8}{3})^2+ (z - \dfrac{8}{3})^2$

∴

This is a sphere with a center $(\dfrac{8}{3},\dfrac{8}{3},\dfrac{8}{3} )$ and ;

radius; $\sqrt{\dfrac{16}{3}}$

$= \dfrac{4 \sqrt{3}}{3}$

6 0

3 years ago

The scatterplot shows the relationship between the number of slices of pizza eaten by each member of a football team (x) and the

ivolga24 [154]

Answer:

5.31

Step-by-step explanation:

Given the regression line equation, $y = 10 - 0.67x$ , where,

x = number of slices of pizza eaten

y = number of laps run immediately

Number of laps run by a player who ate 7 slices of pizza can be predicted by plugging in x = 7 into the regression line equation to find y:

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$y = 10 - 0.67(7)$

$y = 10 - 4.69$

$y = 5.31$

5 0

3 years ago

Please help me! This is is rational function and I don’t know how to/ don’t remember how do this! How would I find and write the

ivanzaharov [21]

An answer is

$\displaystyle f\left(x\right)=\frac{\left(x+1\right)^3}{\left(x+2\right)^2\left(x-1\right)}$

Explanation:

Template:

$\displaystyle f(x) = a \cdot \frac{(\cdots) \cdots (\cdots)}{( \cdots )\cdots( \cdots )}$

There is a nonzero horizontal asymptote which is the line y = 1. This means two things: (1) the numerator and degree of the rational function have the same degree, and (2) the ratio of the leading coefficients for the numerator and denominator is 1.

The only x-intercept is at x = -1, and around that x-intercept it looks like a cubic graph, a transformed graph of $y = x^3$ ; that is, the zero looks like it has a multiplicty of 3. So we should probably put $(x+1)^3$ in the numerator.

We want the constant to be a = 1 because the ratio of the leading coefficients for the numerator and denominator is 1. If a was different than 1, then the horizontal asymptote would not be y = 1.

So right now, the function should look something like

$\displaystyle f(x) = \frac{(x+1)^3}{( \cdots )\cdots( \cdots )}.$

Observe that there are vertical asymptotes at x = -2 and x = 1. So we need the factors $(x+2)(x-1)$ in the denominator. But clearly those two alone is just a degree-2 polynomial.

We want the numerator and denominator to have the same degree. Our numerator already has degree 3; we would therefore want to put an exponent of 2 on one of those factors so that the degree of the denominator is also 3.

A look at how the function behaves near the vertical asympotes gives us a clue.

Observe for x = -2,

as x approaches x = -2 from the left, the function rises up in the positive y-direction, and
as x approaches x = -2 from the right, the function rises up.

Observe for x = 1,

as x approaches x = 1 from the left, the function goes down into the negative y-direction, and
as x approaches x = 1 from the right, the function rises up into the positive y-direction.

We should probably put the exponent of 2 on the $(x+2)$ factor. This should help preserve the function's sign to the left and right of x = -2 since squaring any real number always results in a positive result.

So now the function looks something like

$\displaystyle f(x) = \frac{(x+1)^3}{(x+2 )^2(x-1)}.$

If you look at the graph, we see that $f(-3) = 2$ . Sure enough

$\displaystyle f(-3) = \frac{(-3+1)^3}{(-3+2 )^2(-3-1)} = \frac{-8}{(1)(-4)} = 2.$

And checking the y-intercept, f(0),

$\displaystyle f(0) = \frac{(0+1)^3}{(0+2 )^2(0-1)} = \frac{1}{4(-1)} = -1/4 = -0.25.$

and checking one more point, f(2),

$\displaystyle f(2) = \frac{(2+1)^3}{(2+2 )^2(2-1)} = \frac{27}{(16)(1)} \approx 1.7$

So this function does seem to match up with the graph. You could try more test points to verify.

======

If you're extra paranoid, you can test the general sign of the graph. That is, evaluate f at one point inside each of the key intervals; it should match up with where the graph is. The intervals are divided up by the factors:

x < -2. Pick a point in here and see if the value is positive, because the graph shows f is positive for all x in this interval. We've already tested this: f(-3) = 2 is positive.
-2 < x < -1. Pick a point in here and see if the value is positive, because the graph shows f is positive for all x in this interval.
-1 < x < 1. Pick a point here and see if the value is negative, because the graph shows f is negative for all x in this interval. Already tested since f(0) = -0.25 is negative.
x > 1. See if f is positive in this interval. Already tested since f(2) = 27/16 is positive.

So we need to see if -2 < x < -1 matches up with the graph. We can pick -1.5 as the test point, then

$\displaystyle f(-1.5) = \frac{\left(-1.5+1\right)^3}{\left(-1.5+2\right)^2\left(-1.5-1\right)} = \frac{(-0.5)^3}{(0.5)^2(-2.5)} \\= (-0.5)^3 \cdot \frac{1}{(0.5)^2} \cdot \frac{1}{-2.5}$

We don't care about the exact value, just the sign of the result.

Since $(-0.5)^3$ is negative, $(0.5)^2$ is positive, and $(-2.5)$ is negative, we really have a negative times a positive times a negative. Doing the first two multiplications first, (-) * (+) = (-) so we are left with a negative times a negative, which is positive. Therefore, f(-1.5) is positive.

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4 years ago

What is the ansrwer to this equation

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Answer:

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Step-by-step explanation:

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In 1906 Kennelly developed a simple formula for predicting an upper limit on the fastest time that humans could ever run distanc

umka21 [38]

Answer / Step-by-step explanation:

(1) Given t = 0.0588s ¹.¹²⁵

where s is the distance and t is the time to run that distance.

The second portion asks us to find the derivative of the equation when our s value is equal to 20 and interpret.

(2) First, we try to convert the unit from miles to meters

Therefore, 1 mile = 1609 meters

Then,

t = 0.0588 ( 1609 ) ¹.¹²⁵

=238 . 09

This gives us the instantaneous rate of change of seconds between every 20 meters ran.

The last portion asks us to compare this estimate to current world records. And have they been surpassed?

As of today, the fastest official record for a standard mile is held by a man from Morocco named Hichan El Guerrouj. The time was recorded at 3.43 minutes in Rome, Italy on July 7th, 1999.

Now, keep in mind that this is almost a full minute slower than the estimated time. However, how do these projections hold up against Usain Bolt, the man that is considered the fastest man in the world ?

Although, Usain Bolt does run long distances, he holds records in nearly every sprinting event that he has ever competed in.

Hence, Kennelly's estimate for the fastest mile is 238.09

(3) Now, noting that since dt / ds = 0.0588 ( 1.25 ) s ⁰.¹²⁵

Then,

dt / ds I 100 = 0.0588 (1.25) (20) ⁰.¹²⁵

= 0.1176

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3 years ago