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3 years ago

Write an equation that models the sequence 200, 500, 1250, ...

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

6 0

The answer could be 200+500+1250=1950

Semenov [28]3 years ago

6 0

If you add 300 to 200, you get 500. If you add 450 to 300, you get 750, and 750 + 500 = 1250. So, i'm thinking it could be 200 + 300 = 500, 300 + 450 = 750, 500 + 750 = 1250. Hope this helps you, and best of luck!!!

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An object is launched on the moon at 16 feet per second (f/s) from a 1152-foot tall tower. The equation for the object's height

alexgriva [62]

Answer:

0.5seconds later

Step-by-step explanation:

Given the height modeled by the equation:

s(t) = -16t^2 + 16t + 1152

The velocity of the object at the moon surface is zero

ds(t)/dt = 0

ds(t)/dt = -32t + 16

0 = -32t + 16

32 t = 16

t = 16/32

t = 1/2

t = 0.5seconds

Hence the object strikes the moon surface 0.5seconds later

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Read 2 more answers

(1 point) The matrix A=⎡⎣⎢−4−4−40−8−4084⎤⎦⎥A=[−400−4−88−4−44] has two real eigenvalues, one of multiplicity 11 and one of multip

serious [3.7K]

Answer:

We have the matrix $A=\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&8&4\end{array}\right]$

To find the eigenvalues of A we need find the zeros of the polynomial characteristic $p(\lambda)=det(A-\lambda I_3)$

Then

$p(\lambda)=det(\left[\begin{array}{ccc}-4-\lambda&-4&-4\\0&-8-\lambda&-4\\0&8&4-\lambda\end{array}\right] )\\=(-4-\lambda)det(\left[\begin{array}{cc}-8-\lambda&-4\\8&4-\lambda\end{array}\right] )\\=(-4-\lambda)((-8-\lambda)(4-\lambda)+32)\\=-\lambda^3-8\lambda^2-16\lambda$

Now, we fin the zeros of $p(\lambda)$ .

$p(\lambda)=-\lambda^3-8\lambda^2-16\lambda=0\\\lambda(-\lambda^2-8\lambda-16)=0\\\lambda_{1}=0\; o \; \lambda_{2,3}=\frac{8\pm\sqrt{8^2-4(-1)(-16)}}{-2}=\frac{8}{-2}=-4$

Then, the eigenvalues of A are $\lambda_{1}=0$ of multiplicity 1 and $\lambda{2}=-4$ of multiplicity 2.

Let's find the eigenspaces of A. For $\lambda_{1}=0$ : $E_0 = Null(A- 0I_3)=Null(A)$ .Then, we use row operations to find the echelon form of the matrix