Point

Dana can type nearly 90 words per minute. Use this information to find the number of hours it will take her to type 2.6 x 105 wo

Vlad1618 [11]

Dana can type 90 words per minute.

Since, 1 minute = $\frac{1}{60}$ hours

Therefore, number of words she can type = $\frac{90}{\frac{1}{60}}$

= 90×60

= 5400 words per hour

If she types $2.6\times 10^5$ words in 'x' hours.

Number of words Dana types with the given speed in 'x' hours = Speed of typing × Time

= $5400\times x$

Therefore, $5400\times x =2.6\times 10^5$

$5400x=260000$

$x=\frac{260000}{5400}$

$x=48.15$ hours

Therefore, Dana types $2.6\times 10^5$ words in 48.15 hours.

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6 0

3 years ago

One parent is a cystic fibrosis carrier, and the other has

Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0

3 years ago

Five times the sum of a number and 27 is greater than or equal to six times the sum of that num

stepladder [879]

Question:

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.

What is the solution set of this problem?

Answer:

$x \leq -21$