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telo118 [61]
3 years ago
11

Find the number of years it would take for $12,000 to earn simple interest of $324 at an annual interest rate of 6% per year.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0
It will take six years
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What is the probability that a value falls in the interval μ ± 2σ, that computes the probability P(-2 < Z < 2). Round to f
bija089 [108]

Answer:

0.9544    

Step-by-step explanation:

P(-2 < Z < 2) means that Z has mean 0 and standard deviation 2.

P(−2 < Z < 2) = F(2) - F(-2)

Using the Z - table,

F(2) = 0.9772

and F(-2) = 0.0228

Thus,

P(−2 < Z < 2) = 0.9772 - 0.0228 = 0.9544

This means that data within two standard deviation is 95%.

8 0
3 years ago
Sadie finished her math test in sixteen minutes less than three times the amount of times it took her friend Laura to finish.if
amid [387]

Answer:

Sadie took 47 minutes to finish her test.

Step-by-step explanation:

Let Laura's time be x minutes.

Then we have:

x + 3x - 16 = 68

4x = 84

x = 21 minutes.

So Sadie took 3(21) - 16 = 63-16

= 47 minutes.

3 0
3 years ago
How do you solve 235+123 using a number line?
Scrat [10]
You would either start at 0 and go over 235  then you would go over 123 more
6 0
3 years ago
(18) In the right triangle CDE, Angle E
LenKa [72]
Answer: 43 degrees

Explanation: All of the angles inside of a triangle add to equal 180 degrees. All you have to do is subtract the two angle measures from 180 degrees to get the answer.
180-90-47=43 degrees
7 0
2 years ago
(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard
AveGali [126]

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: t_{n-1,\alpha/2}=t_{7,0.025}=2.365

Sample mean : \overline{x}=24.8\text{ hours}

Standard deviation : \sigma=3.2\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

6 0
3 years ago
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