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alexandr1967 [171]

3 years ago

10

a train traveled at an average speed of 45 miles per hour for 2 hours and 30 miles per hour for 3 hours. what is the total numbe

r of miles that the train traveled

2 answers:

Allisa [31]3 years ago

7 0

Distance=rate times time
rate=xmiles per hour
time=y hours

total distance=distance1+distance2
distance1=45mph times 2=90mi
distance2=30mph times 3=90mi
total distance=90mi+90mi=180mi

total is 180mi

Luba_88 [7]3 years ago

6 0

(45×2)+(30×3)= 180 miles

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What are the measurements of the sides of a pentagon that has the area of 32?

LenaWriter [7]

Answer:

4.31 units

Step-by-step explanation:

A pentagon is a polygon with five straight sides.

The formula to apply here will be finding area from side length, assuming that this is a regular pentagon with five sides of equal length.

Lets take each side length to be x units

Divide the pentagon into five triangles by joining a line from the center to any vertex of the pentagon.

Now you have five equal triangle.Take the base triangle and divide it into two(take a line from center of pentagon to hit the base at 90°)

This will divide the base triangle of length x unit into two equal triangles with base length x/2 units.

The angle at the pentagon center for the small formed triangle will be 36°. Here you have a triangle with base x/2 units and angle 36° at top center.

To get the height of the triangle you apply formula for tangent of an angle;

height, h=0.5x /tan 36°

Find area of the small triangle;

Area=1/2 *b*h

where b is base length=0.5x and h is height = 0.5x/tan 36°

Area=1/2*0.5x * (0.5x /tan 36°) Area for one small triangle.

However, you notice that you will have 10 small triangles for the whole pentagon, hence multiply this area by 10 which should be equal to the area of the pentagon given 32.

32=1/2 * 0.5x *(0.5x /tan 36°) *10

32=1.25x² /tan 36°

32*0.7265=1.25x²

18.60=x²

√18.60=x

4.31=x

Measurement of one side is 4.31 units

3 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

Solve this inequality 3q - 6 > 21

erica [24]

3q - 6 > 21

3q > 27

q > 9

6 0

3 years ago

Read 2 more answers

A pair of equations is shown below:

Archy [21]

Slope Intercept Form - y = mx + b

First you need the slope or m which in the first equation is 6 and in the second is 5

Next the y-intercept or b which in the first equation is -4 and in the second is -3

Here is an image of both equation plotted on a graph where the first equation is purple and the second is green

Hope this helps, if you need anything else i will edit it in :)

edit: The to lines intercept at the point (1,2)

Sorry, i wasn't completely sure what you needed i haven't done this in a while. If you still need more, I'll try to help.

4 0

3 years ago

Read 2 more answers

Abigail has a cylindrical candle mold with the dimensions shown. If Abigail has a rectangular block of wax measuring 15 cm by 12

luda_lava [24]

Find the volume of the candle using the formula for volume of a cylinder:

V = PI x r^2 x h = 3.14 x 3.4^2 x 6 = 217.79 cubic cm. Round to 217.8

Find the volume of the block: V = l x w x h = 15 x 12 x 18 = 3,240 cubic cm.

Now divide the volume of the block by the volume of a candle:

3240 / 217.8 = 14.88

Round to the nearest tenth = 14.9 candles.

3 0

4 years ago