Δx→0 −5(x + Δx) + 5x Δx

1 answer:

7 0

I guess the original function was

y = 5x (1)

y+Δy =5(x+Δx) (2)

(2) - (1) =

Δy = 5Δx

Δx →0, Δy/Δx →5

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