-1.3 is farther from 0 because -1.3 is less than negative one, where as 4 fifths is more than negative one. -1.3 is farther.
Given that Point T is on line segment SU, the numerical value of segment TU is 12.
<h3>What is the numerical value of TU?</h3>
Given the data in the question;
- Point T is on line segment SU
- Segment SU = 3x-7
- Segment ST = x+7
- Segment TU = x-1
- Numerical value of Segment TU = ?
Since Point T is on line segment SU.
Segment SU = Segment ST + Segment TU
Plug in the given values and solve for x
3x - 7 = ( x+7 ) + ( x-1 )
3x - 7 = x + 7 + x - 1
3x - 7 = 2x + 6
3x - 2x = 6 + 7
x = 13
Next, we determine the numerical value of TU
Segment TU = x-1
Plug in value of x
Segment TU = 13 - 1
Segment TU = 12
Given that Point T is on line segment SU, the numerical value of segment TU is 12.
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The population is all of the wild elephants. The sample is the 400 wild elephants selected.
Answer:
The difference between the maximum and minimum is
Step-by-step explanation:
Since p = 10-q, we can replace p in the expression and we get a single-variable function
Taking the derivative with respect to q and using the rule for the derivative of a product
Critical point (where f'(q)=0)
Assuming q≠ 0 and q≠ 10
To check this is maximum, we take the second derivative
and
f''(625/63) < 0
so q=625/63 is a maximum. For this value of q we get p=5/63
The maximum value of
is
The minimum is 0, which is obtained when q=0 and p=10 or q=10 and p=0
The difference between the maximum and minimum is then