I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such
anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent
(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
(4,0)
Step-by-step explanation:
It is a linear function so you find the slope by doing y2-y1/x2-x1 and you find the slope to be 1/2. You can then setup an equation using it and graph it to find the next value.
I think this problem is 3
Answer:
y = 0x - 2/3
Step-by-step explanation:
We are asked to find the equation of the line
Step1: find the slope
( 0 , -2/3) ( 3 , -2/3)
m = (y_2 - y_1 )/ (x_2 - x_1)
x_1 = 0
y_1 = -2/3
x_2 = 3
y_2 = -2/3
Insert the values into the equation
m =( -2/3 - (-2/3) / (3 - 0)
= -2/3 + 2/3 / 3
= 0 / 3
m = 0
Step 2: sub m into the equation
y = mx + c
y = 0x + c
Step 3: sub any of the two points given into the eqn
y = 0x + c
Let's pick ( 3 , -2/3)
x = 3
y = -2/3
-2/3 = 0(3) + c
-2/3 = 0 + c
c = -2/3
Step4: sub c into the equation
y = mx + c
y = 0x + c
y = 0x - 2/3
Therefore, the equation of the line is
y = 0x - 2/3