If 3 consecutive integers sum to 63, the largest of the 3 = ?

Mathematics

2 answers:

Serggg [28]4 years ago

7 0

X+(x+1)+(x+2)=63
3x+3=63
3x=60
x=20
Consecutive integers are: 20, 21, 22
Answer: 22

DochEvi [55]4 years ago

6 0

This problem states that the sum of 3 consecutive integers is 63 and it asks us to find the largest integer.

Three consecutive integers can be represented as followed.

X → first integer

X + 1 → second integer

X + 2 → third integer

Since the sum of our three consecutive integers is 24, we can write an equation.

X + X + 1 + X + 2 = 63

We can simplify our equation on the left and it will read...

<h2>3x + 3 = 63</h2><h2> -3 -3</h2><h2></h2><h2>3x = 60</h2><h2> ÷3 ÷3 ← divide both sides by 3</h2><h2></h2><h2>X = 20</h2><h2></h2><h2>Largest integer = X + 2</h2><h2>20 + 2 = 22</h2><h2></h2><h2>Largest integer = 22</h2>

You might be interested in

What is the equation for g, which is f(x) = 2x2 + 3x − 1 reflected across the y-axis? Group of answer choices g(x) = −2x2 − 3x −

Sergio [31]

Answer:

$g(x) = 2x^2 - 3x - 1$