If 3 consecutive integers sum to 63, the largest of the 3 = ?
2 answers:
X+(x+1)+(x+2)=63
3x+3=63
3x=60
x=20
Consecutive integers are: 20, 21, 22
Answer: 22
This problem states that the sum of 3 consecutive integers is 63 and it asks us to find the largest integer.
Three consecutive integers can be represented as followed.
X → first integer
X + 1 → second integer
X + 2 → third integer
Since the sum of our three consecutive integers is 24, we can write an equation.
X + X + 1 + X + 2 = 63
We can simplify our equation on the left and it will read...
<h2>
3x + 3 = 63</h2><h2>
-3 -3</h2><h2>
</h2><h2>
3x = 60</h2><h2>
÷3 ÷3 ← divide both sides by 3</h2><h2>
</h2><h2>
X = 20</h2><h2>
</h2><h2>
Largest integer = X + 2</h2><h2>
20 + 2 = 22</h2><h2>
</h2><h2>
Largest integer = 22</h2>
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