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mars1129 [50]
2 years ago
15

Re-write the quadratic function below in Standard Form y = 2(x + 5)² + 3.​

Mathematics
1 answer:
zmey [24]2 years ago
7 0

Answer:

2x^{2} +20x+53

Step-by-step explanation:

2(x^2 + 10x + 25) + 3

2x^2 + 20x + 50 + 3

2x^2 + 20x + 53

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Solve the linear equations <br> 1/4(x-5)+4=1/3(2x+7)-5/6
quester [9]

Answer:

x = 3

Step-by-step explanation:

Given the linear equation :

1/4(x-5)+4=1/3(2x+7)-5/6

(x-5)/4 + 4 = (2x+7)/3 - 5/6

Take the lcm and sum

(x-5+16)/4 = (4x+14-5)/6

(x+11)/4 = (4x+9)/6

Cross multiply

6(x+11) = 4(4x+9)

6x + 66 = 16x + 36

Collect like terms

6x - 16x = 36 - 66

-10x = - 30

x = 30/10

x = 3

6 0
3 years ago
What is the equation of the line, in slope-intercept form, that passes through the point (0,7) and is perpendicular to the line
Arisa [49]

Answer:

=12

Step-by-step explanation:


7=3(0)-5

7=-5

7+5

=12


Im pretty sure this is the answer


4 0
3 years ago
Read 2 more answers
Sharon’s turtle escaped from her backyard sometime in the last few hours. According to her calculations, the farthest the turtle
myrzilka [38]
The farthest distance of the turtle can be solved with the following equations:

x = 112 + 4
x = 112 - 4

By solving the equations, we conclude that t<span>he turtle can be found either in the 116th block or the 108th block.</span>
8 0
3 years ago
Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
vladimir2022 [97]
What we know:
line P endpoints (4,1) and (2,-5) (made up a line name for the this line)
perpendicular lines' slope are opposite in sign and reciprocals of each other
slope=m=(y2-y1)/(x2-x1)
slope intercept for is y=mx+b

What we need to find: 
line Q (made this name up for this line) , a perpendicular bisector of the line p with given endpoints of  (4,1) and (2,-5)

find slope of line P using (4,1) and (2,-5) 
m=(-5-1)/(2-4)=-6/-2=3

Line P has a slope of 3 that means Line Q has a slope of -1/3.

Now, since we are looking for a perpendicular bisector, I need to find the midpoint of line P to use to create line Q. I will use the midpoint formula using line P's endpoints (4,1) and (2,-5).

midpoint formula: [(x1+x2)/2, (y1+y2)/2)]
midpoint=[(4+2)/2, (1+-5)/2]
              =[6/2, -4/2]
              =(3, -2)

y=mx=b       when m=-1/3 slope of line Q and using point (3,-2) the midpoint                                 of line P where line Q will be a perpendicular bisector

(-2)=-1/3(3)+b               substitution
-2=-1+b                           simplified
-2+1=-1+1+b                 additive inverse
-1=b

Finally, we will use m=-1/3 slope of line Q and y-intercept=b=-1 of line Q
y=-1/3x-1



4 0
3 years ago
Read 2 more answers
PLEASE HELP MEEE :))))))
Greeley [361]

Step-by-step explanation:

The correct steps are:

2x²-2x-24=0

2(x²-x-12)=0

2(x-4)(x+3)=0

x=4 or x=-3

so what actually went wrong, is the final answer which is supposed to be <em>x=4,-3</em><em> </em>instead of x=-4,3

5 0
2 years ago
Read 2 more answers
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