it's x ≤ 3 :))) I found it out after realizing what you were asking
<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =
factoring with leading coefficient:
for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
a=3, b=-2, c=-8
</span>a*c = 3*(-8) = -24
-24=(-6)*4 and -6+4=-2, so m=-6 and n=4
replace bx with mx + nx and factor by grouping
</span><span>
3x^2 - 2x - 8 = </span>3x^2 -6x + 4x -8 = 3x(x-2) + 4(x-2) = (3x+4)(x-2)
answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>
Answer:
$72.5
Step-by-step explanation:
- Initial value = $200
- Depreciated value after 4 years = $115
<u>Since depreciation rate is linear, then:</u>
- 200 - 4x = 115
- 4x = 200 - 115
- 4x = 85
- x = 85/4
- x = 21.25
<u>Value after 6 years:</u>
- 200 - 6*21.25 = 200 - 127.5 = $72.5
Answer:
The answer to this question is A
Answer:
'''
Step-by-step explanation:
