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Evgesh-ka [11]
3 years ago
10

Each situation described bellow requires inference about a mean or means. Identify each as involving (1) a single sample, (2) ma

tched pairs, or (3) two independent samples.
1- Looking back on love. Choose 40 romantically attached couples in their midtwenties. Interview the man and woman separately about a romantic attachment they had at age 15 or 16. Compare the attitudes of men and women.
2- Chemical analysis. To check a new analytical method, a chemist obtains a reference specimen of known concentration from the National Institute of Standards and Technology. She then makes 20 measurements of the concentration of this specimen with the new method and checks for bias by comparing the mean result with the known concentration.
3- Chemical analysis, continued. Another chemist is checking the same new method. He has no reference specimen, but a familiar analytic method is available. He wants to know if the new and old methods agree. He takes a specimen of unknown concentration and measures the concentration 10 times with the new method and 10 times with the old method.
Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

1) matched samples

2) single sample

3) independent samples

Step-by-step explanation:

1) couples were taken and their behaviors matched

2) only one sample was used

3) two different samples were used and their average compared.

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CAN U GUYS PLZ HELP!!
attashe74 [19]

Answer:

C. 5/2

Step-by-step explanation:

Two points that the graph passes through are (-5, -4) and (-3, 1). This tells us that the graph goes up 5 units at the same rate that it goes right 2 units. Since the slope of a graph is simply the movement of the y values over the movement of the x values, the slope of this graph is 5/2, which is option C.

6 0
3 years ago
1.05055 trillion divided by 6.005 billion<br><br>Free Points
Dmitrij [34]

Answer:

0.17494587

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
the length of a rectangle is 6 inches longer than its width. If the perimeter of the rectangle is 76in. Find its length and widt
DerKrebs [107]

The length and the width of the rectangle are 22 inches and 16 inches respectively

<h3>How to determine the length and the width of the rectangle?</h3>

The given parameters are:

Length = 6 inches + width

Perimeter = 76 inches

The perimeter is calculated as:

Perimeter = 2 * (Length + Width)

This gives

76 inches = 2 * (6 inches + Width + Width)

Divide through by 2

38 inches = 6 inches + Width + Width

Evaluate the like terms

2 * Width = 32 inches

Divide both sides by 2

Width = 16 inches

Substitute Width = 16 inches in Length = 6 inches + width

Length = 6 inches + 16 inches

Evaluate

Length = 22 inches

Hence, the length and the width of the rectangle are 22 inches and 16 inches respectively

Read more about perimeters at:

brainly.com/question/24571594

#SPJ1

4 0
2 years ago
PLEASE HELP!! URGENT
Slav-nsk [51]

1. The problem statement tells you to find "the area of the hexagonal face".

2. If we assume the intent is to find the shaded area of the face only, it differs from the area of a regular hexagon in that there is a hole in the middle.

3. You must find the area of the regular hexagon, and subtract the area of the circular hole in the middle.

4. The formula for the area of a circle in terms of its radius is

... A = πr²

5. The formula for the area of a regular hexagon in terms of the radius of the circumcircle is

... A = (3√3)/2·r²

6. The radius of the circumcircle of the regular hexagon is given. No additional information is needed.

7. You can use the trig functions of the angles of an equilateral triangle to find the apothem, but there is no need for that when you use the formula of 5.

8. All this is unnecessary. The apothem is (8 mm)·(√3)/2 = 4√3 mm ≈ 6.9282 mm, the shorter leg is (8 mm)·(1/2) = 4 mm. The perimeter is 6·8 mm = 48 mm.

9. The area of the hexagon is

... A = 3√3/2·(8 mm)² = 96√3 mm² ≈ 166.277 mm²

10. The area of the circle is

... A = π·(4 mm)² = 16π mm² ≈ 50.265 mm²

11. The area of the hexagonal face is approximately ...

... 166.277 mm² - 50.265 mm² = 116.01 mm²

6 0
3 years ago
The length of a planet's orbit around a star is approximately 29,870,000 km.
Sliva [168]

Answer:

745 k/hr

Step-by-step explanation:

mathematically, 1 day = 24 hours

1670 days = 1670 * 24 = 40,080 hours

The speed is thus;

(29,870,000)/40,080 = 745.259

= 745 km/h

5 0
3 years ago
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