Each situation described bellow requires inference about a mean or means. Identify each as involving (1) a single sample, (2) ma
1 answer:
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Answer:
a. 1.44
Step-by-step explanation:
We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.
At the null hypothesis, it is tested if the proportion is of at most 40%, that is:
At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.4 is tested at the null hypothesis:
This means that
A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.
This means that:
Value of the test statistic:
Thus the correct answer is given by option a.
Answer:
1138
Step-by-step explanation:
From the information given:
We can represent it perfectly in an exponential form:
where;
p = initial value = 120
q = base of the exponential form
q = 1 + r
here; r = rate in decimal = 10% = 0.1
Then q can now be = 1 + 0.1 = 1.1
Replacing it into the exponential form, we get:
where;
x = number of days and m = number of shoppers
Thus:
For the first day:
m = 120
For the second day:
m = 132
For the third day:
m = 145.2
For the fourth day
m = 159.72
For the fifth-day
m = 175.692
For the sixth-day
m = 193.2612
For the seventh-day
m = 212.58732
Thus; the total numbers of shoppers for the first 7 days is:
= 1138.46052
≅ 1138