Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
13 units
Step-by-step explanation:
Distance formula: 
Simply plug in your variables




d = 13
The answer is the second sentence
3 ones = 3
7 hundredths = 7/100
So equivalent fraction is 3 7/100 or 307/100.
Equivalent decimal is: 3.07
Answer:
The answer is 12
Step-by-step explanation:
Step 1: $26.95 - $8.95 (which equals $18.00)
Step 2: 18 divided by 1.50 (which equals 12)