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Misha Larkins [42]
3 years ago
13

Kilogram abbreviation

Mathematics
2 answers:
loris [4]3 years ago
6 0

Answer:

Kg

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
6 0

Answer:

(Kg)

Step-by-step explanation:

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Would you rather
hjlf

Answer:

option A sounds like a better deal if that's what your asking.

4 0
3 years ago
How do you graph 2x+4y=20
Zanzabum

Divide by 2 on each side: x+2y=10

If y is 0, x=10. If x=0, y=5.

x-intercept: (10, 0)

y-intercept: (0, 5)

Draw those two points, connect, and extend.

4 0
4 years ago
Consider the line y equals 2 over 5 x plus 4.
crimeas [40]

the parallel linear equation is:

y = (2/5)*x - 3

<h3></h3><h3>How to find the parallel line?</h3>

Two lines are parallel if the lines have the same slope but different y-intercept.

Here we know the line equation:

y = (2/5)*x + 4

Then a parallel line is of the form:

y = (2/5)*x + c

Where c is different than 4.

We want this line to pass through (5, -1), then:

-1 = (2/5)*5 + c

-1 = 2 + c

-1 - 2 = -3 = c

Then the parallel linear equation is:

y = (2/5)*x - 3

If you want to learn about linear equations:

brainly.com/question/1884491

#SPJ1

3 0
2 years ago
A line passes through the points (−3,1) and (1,−2). This line can be modeled by the equation y=ax+b. What are the values (in fra
victus00 [196]

Answer:

see explanation

Step-by-step explanation:

y = ax + b is the equation in slope- intercept form

where a is the slope of the line and b is the y- intercept

To find a use the slope formula

a = (y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 1) and (x₂, y₂ ) = (1, - 2)

a = \frac{-2-1}{1+3} = - \frac{3}{4} = - 0.75, hence

y = - 0.75 + b

To find b substitute either of the 2 points into the equation

using (1, - 2), then

- 2 = - 0.75 + b ⇒ b = - 2 + 0.75 = - 1.25 = - 1 \frac{1}{4}



7 0
3 years ago
Complete the equation of the line through (-10,3) and (-8,-8)
Alina [70]

Answer: 2y + 11x = -104

Step-by-step explanation:

The formula for calculating equation of line given two points is :

\frac{y-y_{1}}{x-x_{1}} = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

x_{1} = -10

x_{2} = -8

y_{1} = 3

y_{2} = -8

substituting the values into the formula , we have :

\frac{y-3}{x-(-10)} = \frac{-8-3}{-8-(-10)}

\frac{y - 3}{x + 10} = \frac{-11}{2}

2(y - 3 ) = -11 ( x +10 )

2y - 6 = -11x - 110

2y + 11x = -110 + 6

2y + 11x = -104

Therefore : the equation of the line in standard form is 2y + 11x = -104

8 0
3 years ago
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