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Morgarella [4.7K]
3 years ago
9

Sofia graphed the points 1.3, −11 2 , 0.25, and 13 4 on the number line. A number line going from negative 2 to positive 2 in in

crements of 1. There are 2 equal spaces between each number. A point is halfway between negative 2 and negative 1. A point is halfway between 0 and the mark to the right of 0. A point is slightly to the left of the mark to the right of 1. A point is halfway between the mark to the left of 2 and 2. Then she used the number line to order the numbers from least to greatest. -11 2 , 0.25, 13 4 , 1.3 Which statements about Sofia’s work are true? Select all that apply. She graphed the points correctly. She did not graph the points correctly. She ordered the numbers correctly. She did not order the numbers correctly. She correctly ordered Negative 1 and one-half as the least. She correctly ordered 1.3 as the greatest.
Mathematics
2 answers:
Irina18 [472]3 years ago
5 0

Answer:

<h2>ofia graphed the points 1.3, −11 2 , 0.25, and 13 4 on the number line. A number line going from negative 2 to positive 2 in increments of 1. There are 2 equal spaces between each number. A point is halfway between negative 2 and negative 1. A point is halfway between 0 and the mark to the right of 0. A point is slightly to the left of the mark to the right of 1. A point is halfway between the mark to the left of 2 and 2. Then she used the number line to order the numbers from least to greatest. -11 2 , 0.25, 13 4 , 1.3 Which statements about Sofia’s work are true? Select all that apply. She graphed the points correctly. She did not graph the points correctly. She ordered the numbers correctly. She did not order the numbers correctly. She correctly ordered Negative 1 and one-half as the least. She correctly ordered 1.3 as the greatest.</h2>

Step-by-step explanation:

never [62]3 years ago
5 0
There’s a equal of 2 spaces
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Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

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   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

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Step-by-step explanation:

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Solve:
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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \dfrac{2x - 1}{5}  =  \dfrac{x -  2}{2}

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