We have the following expression
![4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})](https://tex.z-dn.net/?f=4%5Ccdot%5Ctext%7Bcis%28%7D%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5Ccdot5%5Ctext%7Bcis%28%7D%5Cfrac%7B%5Cpi%7D%7B6%7D%29)
This is equivalent to
![4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=(4\times5)cis(\frac{\pi}{4}+\frac{\pi}{6})](https://tex.z-dn.net/?f=4%5Ccdot%5Ctext%7Bcis%28%7D%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5Ccdot5%5Ctext%7Bcis%28%7D%5Cfrac%7B%5Cpi%7D%7B6%7D%29%3D%284%5Ctimes5%29cis%28%5Cfrac%7B%5Cpi%7D%7B4%7D%2B%5Cfrac%7B%5Cpi%7D%7B6%7D%29)
Since
![\frac{\pi}{4}+\frac{\pi}{6}=\frac{6\pi+4\pi}{24}=\frac{10}{24}\pi=\frac{5}{12}\pi](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%2B%5Cfrac%7B%5Cpi%7D%7B6%7D%3D%5Cfrac%7B6%5Cpi%2B4%5Cpi%7D%7B24%7D%3D%5Cfrac%7B10%7D%7B24%7D%5Cpi%3D%5Cfrac%7B5%7D%7B12%7D%5Cpi)
we have that
![4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=20cis(\frac{5\pi}{12})](https://tex.z-dn.net/?f=4%5Ccdot%5Ctext%7Bcis%28%7D%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5Ccdot5%5Ctext%7Bcis%28%7D%5Cfrac%7B%5Cpi%7D%7B6%7D%29%3D20cis%28%5Cfrac%7B5%5Cpi%7D%7B12%7D%29)
Therefore, the answer is the second option from top to bottom.
Well lets see. if you're being specific about the rigor, then the period means that <span>cos(2Π÷3(x+α))=cos(2Π÷3(x))</span>Therefore this gives <span>2π÷3α=2π</span>so α = 3.
Hope this can help you
Answer:
She can make 28 packages in total with nothing left over.
Step-by-step explanation:
616÷22=28
Answer:
Value of ![x=30](https://tex.z-dn.net/?f=x%3D30)
Step-by-step explanation:
When the two lines being crossed are Parallel Lines the Corresponding Angles are equal.
Hence
![x+25=55\\\\x=30](https://tex.z-dn.net/?f=x%2B25%3D55%5C%5C%5C%5Cx%3D30)