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pickupchik [31]
3 years ago
15

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,

32 feet, and 48 feet long. If the two shortest sides of quadrilateral EFGH are 9 feet long and 18 feet long, how long is the 2nd longest side on quadrilateral EFGH?
Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

  24 feet

Step-by-step explanation:

The second longest side of ABCD is 32, and the second shortest side of that quadrilateral is 24. Then we can expect the second longest side of EFGH to be 32/24 times the length of its second shortest side:

  (32/24)×(18 feet) = (4/3)×18 feet = 24 feet

The length of the 2nd longest side of EFGH is 24 feet.

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AlladinOne [14]

Answer:

y = 3 and y = x + 3

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The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.

Consider the equation y = x + 3.

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Find the value of x, y and z
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Answer:

Step-by-step explanation:

8x = 9x - 7

-x = -7

x = 7

9(7)-7= 63-7=56

8(7)= 56

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13y=117

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13(9)+7= 117+7= 124

5y-11+56=90

5y+45=90

5y=45

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7 0
3 years ago
The base of a triangular prism is an isosceles right triangle with a hypotenuse of 32−−√ centimeters. The height of the prism is
Roman55 [17]
Isosceles triangle: two equal sides.
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 root (32) = root (L ^ 2 + L ^ 2)
 root (32) = root (2L ^ 2)
 root (32) = Lraiz (2)
 root (32) / root (2) = L
 The surface area is:
 Area of the base and top:
 A1 = (1/2) * (root (32) / root (2)) * (root (32) / root (2))
 A1 = (1/2) * (32/2)
 A1 = (1/2) * (16)
 A1 = 8
 Area of the rectangles of equal sides:
 A2 = (root (32) / root (2)) * (6)
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 Rectangle area of different side:
 A3 = (root (32)) * (6)
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 The area is:
 A = 2 * A1 + 2 * A2 + A3
 A = 2 * (8) + 2 * (24) + (33.9411255)
 A = 97.9411255
 Round to the nearest tenth:
 A = 97.9 cm
 Answer:
 The surface area of the triangular prism is:
 
A = 97.9 cm
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