First thing you want to do is find the length of the missing side where the the right angle is at. You can find that with the pythagorean theorem of the other triangle, since you are already given 2 sides.

Pythagorean Theorem

${a}^{2} + {b}^{2} = {c}^{2}$

a=2

b=?

c=2√2

Plug in and solve for b.

2^2+b^2=(2√2)^2

4+b^2=8

b^2=4

b=2

Now use the pythagorean theorem again to find your x side.

a=2

b=12

c=?

2^2+12^2=c^2

4+144=c^2

148=c^2

c=√148

c=2√37

4 0

3 years ago

How do I solve this 1-2

zepelin [54]

Answer:

1. 1.

2. 62.

Use PEMDAS.

6 0

3 years ago

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6cos(20πt-π)+6√3cos(20πt-π\2)

juin [17]

Answer:

Answer is -6t

Step-by-step explanation:

${ \tt{ = (6 \cos(20\pi t) \cos(\pi) + 6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t) \cos( \frac{\pi}{2} ) + \sin(20\pi t) \sin( \frac{\pi}{2} )) }} \\ = { \tt{ (- 6t + 0) + (0 + 0)}} \\ = { \tt{ - 6t}}$

Note that π is 180°

5 0

3 years ago

ABC DEF AB corresponds to DF. True False

Alex Ar [27]

it's false

I guess

have a nice day

6 0

3 years ago

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