Question

Corners of equal size are cut from a square with sides of length 8 meters (see figure).

Answer 1

we know that

the area of the complete square is equal to

$As=b^{2}$

where

b is the length side of the square

$b=8m$

so

$As=8^{2}$

$As=64$m²

the area of one corner is equal to the area of a triangle

$\frac{x^{2}}{2}$

so

the area of $4$ corners is equal to

$\frac{x^{2}}{2}*4=2x^{2}$

the area A of the resulting figure as a function of x is equal to

area of the square minus the area of $4$ corners

$A=(64-2x^{2})$m²

the answer is

$A=(64-2x^{2})$m²

Answer 2

The area ( A ) of the resulting figure:
A = s² - 4 · x²/2 
A = 8² - x² / 2
A = 64 - x²/2
Answer:
The area is 64 - x² / 2.