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2 years ago

Need help with solving and understanding

Mathematics

1 answer:

prohojiy [21]2 years ago

5 0

Let start off with 5/8+7/8= 1 4/8
Now it's 13+1 4/8= 14 4/8 or 14 1/2 :)

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Given the following geometric sequence, find the common ratio: {16, 64, 256, ...}.

Anettt [7]

Answer:

The common ratio is 4

Step-by-step explanation:

We need to divide a term by the previous term to find the common ratio in a geometric sequence:

64 ÷ 16 = 4

256 ÷ 64 = 4

By doing it twice we can confirm that the common ratio is 4

8 0

2 years ago

Read 2 more answers

Linear pair angles are: Always congruent Sometimes congruent or Never congruent

Grace [21]

Answer:

Always

Step-by-step explanation:

3 0

2 years ago

Which gives 55+100 as a product of gcf and a sum?

defon

Answer:

55+100=155

Step-by-step explanation:

c.5(10+50)

I hope it helped

5 0

2 years ago

The 5th term in a geometric sequence is 120. The 7th term is 30. What are the possible values of the 6th term of the sequence.

klemol [59]

Answer:

± 60

Step-by-step explanation:

aₙ = a₁ * rⁿ⁻¹

a₇ = 30 = a₁ * r⁷⁻¹ = a₁ * r⁶ (1)

a₅ = 120 = a₁ * r⁵⁻¹ = a₁ * r⁴ (2)

(1)/(2): 30/120 = 1/4 = r²

r = ± 1/2 or ± 0.5

a₁ = a₇/r⁶ = 30/0.5⁶ = 1920

a₆ = 1920 * (± 1/2)⁶⁻¹ = 1920 * ± 1/32 = ± 60

3 0

2 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

2 years ago