Answer: Volume of cylinder is (3.14) x (radius squared) times height, or nr^2h
Step-by-step explanation:
As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
Answer:
F(-3) = -5
Step-by-step explanation:
I got it right on the test
Answer:

Step-by-step explanation:
We are given that
Width of pool, b=4.5 m
We have to find the inequality which represents the possible lengths of the wading pool.
Let x be the length of wading pool
We know that
Area of rectangle=
According to question
Using the formula

Divide by 4.5 on both sides we get


Answer:
The first and second iteration of Newton's Method are 3 and
.
Step-by-step explanation:
The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form
based on the following formula:

Where:
- i-th Approximation, dimensionless.
- (i+1)-th Approximation, dimensionless.
- Function evaluated at i-th Approximation, dimensionless.
- First derivative evaluated at (i+1)-th Approximation, dimensionless.
Let be
and
, the resultant expression is:

First iteration: (
)



Second iteration: (
)


