Answer:
2. 8:45am to 5:15pm
Step-by-step explanation:
Looking at the table of John's times, he arrived at 8:42am and left at 5:14pm. If you are rounding to the nearest quarter hour, or 15 minutes, you time would need to be at the hour, 15 minutes after, 30 minutes after or 45 minutes after. Given those options, the closest times would be 8:45am and 5:15pm.
3.75 pounds in 60 ounces. :)
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Number 6 and 7 are incorrect and I can't read 1/2/3
for 6
7/10 would be 70%
for 7
3 2/5 would be 3.40 not 3.25
Use trigonometry.
tan30° = perpendicular / base
Here for angle 30° , x is perpendicular while 10 is the base.
tan30° = 1/√3
1/√3 = x/10
x = 10/✓3
By rationalising
x = 10√3/3
Hope This Helps You!
