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Answer:
Step-by-step explanation:
3. slope of CB = rise/run = 5/12 BF = 5 CF = 12
BF ⊥ DF
DB (seg of two farthest points) = √BF²+DF² = √5²+32² = √1049 = 32.4
4. f(x) = 2x² - 5x -3 vertex : A (h,k) for f(x) = ax² + bx +c
h = - b/2a = - (-5 / 4) = 5/4
f = f(h) = 2*(5/4)² - 5*(5/4) - 3 =25/8 - 25/4 -3 = -49/8
A (5/4 , - 49/8) i.e. (1.25 , - 6.13)
negative root: 2x² - 5x -3 = (2x+1) (x- 3) x = - 1/2 y = 0
B (- 1/2 , 0)
x coordinate of AB: 1/2 (1.25 + -0.5) = 0.375
Answer:
C
Step-by-step explanation:
The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.
Given y = f(x) then f(x + a) is a horizontal translation of a units
• If a > 0 then shift to the left of a units
• If a < 0 then shift to the right of a units
Here shift to the right of 1 unit, thus
y = f(x - 1)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note the y- coordinates are the negative of each other, thus
- y = f(x)
Now = - y, hence
The equation for the red graph is
= f(x - 1) → C
Price per box, P = $1.45 .
Money left, M = $1247 - $472.70 = $774.3 .
Let, number of boxes are x.
So,
Therefore, they have to sell 534 more boxes.
Hence, this is the required solution.