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3 years ago

Sam has a cheese spreader in the shape below.

Mathematics

2 answers:

IRINA_888 [86]3 years ago

5 0

Answer:

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

5 0

Answer:the answer would be C

Step-by-step explanation:

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Will give brainliest

VikaD [51]

Answer: The number of the adult tickets is 168

Step-by-step explanation: * Lets explain how to solve the problem

- The adults ticket costs $10.50

- The students ticket costs $3.75

- The total money of the opening night is $2071.50

- The equation of the total money earned in the opening night is:

10.50 a + 3.75 b = 2071.50, where a is the number of the adult ticket

and b is the number of the student ticket

- There were 82 students attended

* Lets solve the problem

∵ 10.50 a + 3.75 b = 2071.50

∵ The number of the students attended is 82

∵ b is the number of the students

∴ b = 82

- Substitute the value of b in the equation

∴ 10.50 a + 3.75(82) = 2071.50

∴ 10.50 a + 307.5 = 2071.50

- Subtract 307.5 from both sides

∴ 10.50 a = 1764

- Divide both sides by 10.50

∴ a = 168

∵ a is the number of the adult tickets

∴ The number of the adult tickets is 168

Give credit to ashraf 82

8 0

3 years ago

ASAP ANYONE PLEASE tell me if I’m right !

pantera1 [17]

Answer:

no it is d

Step-by-step explanation:

put a value in for t and work it out for each problem i used 2

3 0

3 years ago

Read 2 more answers

Simplify y - 3 over 3 +12

Hitman42 [59]

Answer:

y-3/15

Step-by-step explanation:

5 0

3 years ago

If two marbles are randomly selected from the bag without replacement, what is the probability that the first marble is blue?

joja [24]

Answer:1,0.5, or 0 it depends

Explanation:

The probability that one event occurred depends on the total of random event, being 1 the most of the probabilities

If the two marbles are blue the probability to select a marble blue is 1

If one of the marbles is blue and the other marble is of any color the probability to select the blue marbles is:

P=1 - 1/2=1/2

Being 1/2 or 0.5 the answer

If any of the marbles are blue then the probabilities are 0

8 0

3 years ago

Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the

bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = $\frac{(24-17)}{(24-13)}$

P = $\frac{7}{11}$

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = $\frac{(21-17)}{(24-13)}$

P = $\frac{4}{11}$

P = 0.3636

and

Let the upper quartile be Q

$\frac{(24 - Q)}{(24 - 13)} = 0.25$

$\frac{(24 - Q)}{11} = 0.25$

(24 - Q) = 2.75

Q = $21.25

and

P(X > 20 | X > 16)

P = $\frac{(24-20)}{(24-16)}$

P = $\frac{4}{8}$

P = 0.5

3 0

4 years ago