Answer:
Input Data :
Point 1(xA,yA)(xA,yA) = (4, 3)
Point 2(xB,yB)(xB,yB) = (3, -2)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2
Solution :
Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2
= √(−1)2+(−5)2(-1)2+(-5)2
= √1+251+25
= √2626 = 5.099
Distance between points (4, 3) and (3, -2) is 5.099
Answer:
2x(5x + 14) + 15
Step-by-step explanation:
Given: (2 + 3)(4x + 5) - 8x(
- 2)
(2 + 3)(4x + 5) - 8x(
- 2) = 2
(4x + 5) + 3(4x + 5) - 8x(
- 2)
= (8 + 10
+ 12x + 15) - 8
+ 16x
= 8 + 10
+ 12x + 15 - 8
+ 16x
collecting like terms to have,
8- 8
+ 10
+ 12x + 16x + 15
10 + 28x + 15
Thus,
(2 + 3)(4x + 5) - 8x(
- 2) = 10
+ 28x + 15
= 2x(5x + 14) + 15