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chubhunter [2.5K]
3 years ago
5

Verify the identity. cos 4x + cos 2x = 2 - 2 sin^2(2x) - 2 sin^2 x

Mathematics
1 answer:
Advocard [28]3 years ago
8 0
So are you trying to simplify one side to get it to look like the other?
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Solve the equation=3x =15​
kati45 [8]

3x = 15

x = 15/3

x = 5

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Step-by-step explanation:

4 0
3 years ago
The graph of y = x^2 is translated 3 units to the left. The equation for this new graph is:
EastWind [94]
The answer is:
C. Y=(x+3)^2
7 0
2 years ago
An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the
MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}=  1.45

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}=  3.59

6 0
3 years ago
Find the area of a regular decagon with perimeter 100 units. Show all work.
Slav-nsk [51]
A regular polygon has ten (10) equal sides ( since it is regular).
We are given with the perimeter value which is 100 units and the perimeter formula is P = 10a
Solving for a (the side measurement), we have:
100 = 10a
a= 100/10
a =10

We can now proceed in solving the area and the formula is shown below:
Area = 5/2 a√ (5+2√5)
Area = 5/2 * 10√(5+2√5)
Area = 76.94 square units

The answer is 96.94 square units.
4 0
3 years ago
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